Python 如何处理语法错误？

对于我正在做的程序，它通过一个调查式的问题生成一个动漫推荐列表，并有一个CSV文件存储有关动漫的信息，如流派

但是，在运行程序时，我想测试在执行问题时是否会出现语法错误，并在执行所有问题后打印错误。我希望它能做的是，当输入错误时，语法错误会弹出

这就是我所做的：

if adventure == 'yes':
   with open("AnimeGenre3.csv", 'r', newline='') as f:
       for row in csv.reader(f):
            if row[4] == 'yes':
               anime = str(row[1])
               looping = False
               if anime not in anime_list:
                  anime_list.append(anime)

else:
    print('''
There seems to be a problem in one of the questions
    ''')

比如说，‘你喜欢动画吗’，然后你输入6，语法错误的东西会弹出，然后重新提问。但在完成所有问题并生成动画列表后，它就会弹出

另一个问题是，在完成问题并打印推荐的动画后，我如何再次启动该程序。它会问你是否想重新开始，但它最终没有这样做。这就是我所做的

StartAgain = str(input('Do you like to start again; yes or no: '))

if StartAgain == 'yes':
     print('''
Let's begin ''')
break
if StartAgain == 'no':
      print('thank you for coming')

else:
  print('''
 Sorry Man got to do it again''')

 # an if statement if the user wants to start again
 # this should rerun the program.

现在，这是我到目前为止所做的全部程序，我真的需要找到一种使它更简单的方法，希望我的注释足够好

 import csv
 anime_list = []
 #in the csv AnimeGenre3.csv it contains information such as the animes, the number of 
 episodes and genres

#printing information about the program.
#has an if statement to identify if it user wants to start the program.

looping1 = True
looping2 = True

print('This is a program that identifies specific anime for you')

while looping1 == True:
begin = str(input('Do you like to start; yes or no: '))

if begin == 'yes':
    print('''
Let's begin
''')
    break
if begin == 'no':
    print('thank you for coming')
else:
    print('''
Sorry Man got to do it again
        ''')
#this section is where the program ask the user questions from there
# it will identify, the genres the user is interested in.

while looping2 == True:

action = str(input('Do you like action; yes or no: '))
adventure = str(input('Do you like adventure; yes or no: '))
print('')
print('recommended anime')
#having to use if statements to find any anime that either say "yes" in the CSV file
# it sorts out all of the sorts that the user said yes to.
# It goes through the rows to identify all of the user genres that say yes
# it should print out the recommend anime
# this prints out a long list of anime

if action == 'yes':
    with open("AnimeGenre3.csv", 'r', newline='') as f:
        for row in csv.reader(f):
            if row[3] == 'yes':
                anime = str(row[1])
                looping = False
                if anime not in anime_list:
                    anime_list.append(anime)
                    
if adventure == 'yes':
    with open("AnimeGenre3.csv", 'r', newline='') as f:
        for row in csv.reader(f):
            if row[4] == 'yes':
                anime = str(row[1])
                looping = False
                if anime not in anime_list:
                    anime_list.append(anime)

else:
    print('''
There seems to be a problem in one of the questions
        ''')
# if there is a syntax error within the program, it should pop up to the user saying this
    
print(anime_list)

StartAgain = str(input('Do you like to start again; yes or no: '))

if StartAgain == 'yes':
    print('''
Let's begin ''')
    break
if StartAgain == 'no':
    print('thank you for coming')

else:
    print('''
Sorry Man got to do it again''')

# an if statement if the user wants to start again
# this should rerun the program.

---

关于重新开始，您唯一的代码将打印一条语句。它不重复一个功能。您可能需要考虑进一步调整（组织）程序，以便在重新启动时能够调用函数。例如：

def main()
      //this contains your overall logic, starting/ending the program and/or repeating it
     // at some point in time, you call animeselector() to start, and if it needs repeating, you call it again

 def animeselector ()
      //this controls the in/out and selection process

就确保输入格式正确而言，这可能是另一个功能。它只需检查答案是“是”还是“否”，如果不是，则更改一个变量（如BADANSTALL==false变为true）。然后，当你想要的时候，它会触发其他的事情（重做）

---

我建议查看函数组织的“艰苦学习Python”（后面的章节），一些PyGame教程也有助于了解如何更好地调整编程（因为如果制作游戏，您需要一个整体函数来运行游戏，然后需要一组较小的函数来处理游戏中的活动）.

要么你在这个问题上的第一句话是谎言，要么你在8月31日的问题上的第一句话是谎言。不必要的内容是不被鼓励的，我不知道当这是一个谎言时该说什么——老实说，我没有太多编程经验@sааааааааааааааааӽ那么你应该先学习编程。这样的捷径真的不会带你去任何地方。我只是想知道我做错了什么@在我的程序中，我应该把“def main（）”和“def animeselector（）”放在哪里？看看我推荐的资源。并没有一个正确的方法，但main只会处理start、repeat、call其他函数，end。animeselector处理大部分真实逻辑，除非您可能分离出输入检查器。