Python 基于现有列的值创建新列

我想创建一个新列（即Winning_Time），如下表所示。比赛状态（获胜）的所有时间差将存储在新列获胜时间中。其余行将用NaN或零填充。 我该怎么做

gsm_id  Goal_Flag   Union_Level Team_SR Match_state   Time_diff           Wining_Time
2462796 First goal  Scored      Burnley  Winning    0 days 00:23:15.00   0 days 00:23:15.00
2462796 First goal  Conceded    Chelsea  Losing     0 days 00:23:15.00   NaN               
2462796 Other goals Scored      Burnley  Winning    0 days 00:15:20.00   0 days 00:15:20.00
2462796 Other goals Conceded    Chelsea  Losing     0 days 00:15:20.00   NaN
2462796 Other goals Scored      Burnley  Winning    0 days 00:03:34.00   0 days 00:03:34.00
2462796 Other goals Conceded    Chelsea  Losing     0 days 00:03:34.00   NaN
2462796 Other goals Scored      Chelsea  Losing     0 days 00:25:59.00   NaN
2462796 Other goals Conceded    Burnley  Winning    0 days 00:25:59.00   0 days 25:59.00
2462796 Last goal   Scored      Chelsea  Losing     0 days 00:19:11.00   NaN
2462796 Last goal   Conceded    Burnley  Winning    0 days 00:19:11.00   0 days 00:19:11.00
2462795 First goal  Scored      City     Winning    0 days 01:09:15.00   0 days 01:09:15.00 
2462795 First goal  Conceded    Brighton Losing     0 days 01:09:15.00   NaN
2462795 Last goal   Scored      City     Winning    0 days 00:05:21.00   0 days 00:05:21.00
2462795 Last goal   Conceded    Brighton Losing     0 days 00:05:21.00   NaN

非常感谢您的建议。

您可以使用：

在这里，

numpy.where

就像一个向量化的if/else语句。

您可以使用：

---

这里，

numpy.where

就像一个向量化的if/else语句。

我碰巧发现了。无论如何非常感谢@jppi碰巧发现了这一点。无论如何非常感谢@jpp

df['Winning_Time'] = np.where(df['Match_state'] == 'Winning', df['Time_diff'], np.nan)