Python 按分支和祖先对同一类中的元素进行排序

我得到了以下html（所有元素名称*、名称**、名称***都是未知的）：

---

你能帮我把这两个列表链接到字典里吗？

你可以试试这个脚本。它利用

itertools.groupby

（）将元素分组为键、值：

data = '''<a class="one">nameA</a>
    <a class="two">nameAA</a>
        <a class="three">nameAAA</a>
        <a class="three">nameAAB</a>
    <a class="two">nameAB</a>
        <a class="three">nameABA</a>
        <a class="three">nameABB</a>
<a class="one">nameB</a>
    <a class="two">nameBA</a>
        <a class="three">nameBAA</a>
        <a class="three">nameBAB</a>
    <a class="two">nameBB</a>
        <a class="three">nameBBA</a>
        <a class="three">nameBBB</a>'''

from bs4 import BeautifulSoup
from itertools import groupby

soup = BeautifulSoup(data, 'html.parser')

def get_key_values(soup):
    current_key = None
    for v, g in groupby(soup.select('.one, .three'), lambda k: 'one' in k['class']):
        if v is True:
            current_key = next(g).text
        else:
            yield current_key, [i.text for i in g]

out = dict(get_key_values(soup))

from pprint import pprint
pprint(out)

---

你可以试试这个脚本。它利用

itertools.groupby

（）将元素分组为键、值：

data = '''<a class="one">nameA</a>
    <a class="two">nameAA</a>
        <a class="three">nameAAA</a>
        <a class="three">nameAAB</a>
    <a class="two">nameAB</a>
        <a class="three">nameABA</a>
        <a class="three">nameABB</a>
<a class="one">nameB</a>
    <a class="two">nameBA</a>
        <a class="three">nameBAA</a>
        <a class="three">nameBAB</a>
    <a class="two">nameBB</a>
        <a class="three">nameBBA</a>
        <a class="three">nameBBB</a>'''

from bs4 import BeautifulSoup
from itertools import groupby

soup = BeautifulSoup(data, 'html.parser')

def get_key_values(soup):
    current_key = None
    for v, g in groupby(soup.select('.one, .three'), lambda k: 'one' in k['class']):
        if v is True:
            current_key = next(g).text
        else:
            yield current_key, [i.text for i in g]

out = dict(get_key_values(soup))

from pprint import pprint
pprint(out)

---

请尝试以下代码

itemdict={}
soup=BeautifulSoup(data,'lxml')
for item in soup.select('.one'):
    itemlist = []
    name=item.contents[0].strip()
    for child in item.select('.three'):
        itemlist.append(child.text)
    itemdict[name]=itemlist

print(itemdict)

这应该打印出来

{'nameA': ['nameAAA', 'nameAAB', 'nameABA', 'nameABB'], 'nameB': ['nameBAA', 'nameBAB', 'nameBBA', 'nameBBB']}

---

请尝试以下代码

itemdict={}
soup=BeautifulSoup(data,'lxml')
for item in soup.select('.one'):
    itemlist = []
    name=item.contents[0].strip()
    for child in item.select('.three'):
        itemlist.append(child.text)
    itemdict[name]=itemlist

print(itemdict)

这应该打印出来

{'nameA': ['nameAAA', 'nameAAB', 'nameABA', 'nameABB'], 'nameB': ['nameBAA', 'nameBAB', 'nameBBA', 'nameBBB']}

---

@Mohammadreza您需要导入

pprint

模块：

从pprint导入pprint

@Mohammadreza您需要导入

pprint

模块：

从pprint导入pprint