Python 函数，该函数将Tribonnaci系列返回到一个数字

我正在尝试解决一个练习，该练习要求我编写一个函数，将一个整数作为输入，然后返回一个Tribonaci术语列表，直到输入值。我在很大程度上是“成功的”，但还有一个额外的条件是输出。这是我的代码：

def tribonacci(m):
    tribs = [0, 0, 1]
    if m == 0 or m == 1:
        tribs = [0, 0]
    elif m == 2:
        tribs = [0, 0, 1]
    else:
        while tribs[-1] < m:
            tribs.append(tribs[-1] + tribs[-3] + tribs[-2])
    return tribs  

def tribonacci（m）：
tribs=[0,0,1]
如果m==0或m==1：
tribs=[0,0]
elif m==2：
tribs=[0,0,1]
其他：
当TRIB[-1]

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我知道问题在于while循环，它运行一个额外的迭代，因为最后一个元素仍然不大于m。但是，我无法立即看到如何修复此问题。我会求助于while-else循环，但我想看看其他一些建议。

只需比较一下即将用m生成的术语，如下所示：

def tribonacci(m):
    tribs = [0, 0, 1]
    if m == 0 or m == 1:
        tribs = [0, 0]
    elif m == 2:
        tribs = [0, 0, 1]
    else:
        while tribs[-1] + tribs[-3] + tribs[-2] < m:
            tribs.append(tribs[-1] + tribs[-3] + tribs[-2])

    return tribs

def tribonacci（m）：
tribs=[0,0,1]
如果m==0或m==1：
tribs=[0,0]
elif m==2：
tribs=[0,0,1]
其他：
而TRIB[-1]+TRIB[-3]+TRIB[-2]