Python Mysql json.dump（）用于查看的换行缩进

我使用以下代码行从sql数据库执行和打印数据。出于某种原因，这是唯一对我有效的命令

json_string = json.dumps(location_query_1)

我的问题是，当我打印json_字符串时，它以以下格式显示数据：

Actions.py代码：

class FindByLocation(Action):
    def name(self) -> Text:
        return "action_find_by_location"

    def run (self, dispatcher: CollectingDispatcher,
            tracker: Tracker,
            doman: Dict[Text, Any])-> List[Dict[Text,Any]]:

        global flag
        location =  tracker.get_slot("location")
        price = tracker.get_slot("price")
        cuisine = tracker.get_slot("cuisine")
        print("In find by Location")
        print(location)
        location_query = "SELECT Name FROM Restaurant WHERE Location = '%s' LIMIT 5" % location
        location_count_query = "SELECT COUNT(Name) FROM Restaurant WHERE Location = '%s'" % location

        location_query_1 = getData(location_query)
        location_count_query_1 = getData(location_count_query)

        if not location_query_1:
            flag = 1
            sublocation_view_query = "CREATE VIEW SublocationView AS SELECT RestaurantID, Name, PhoneNumber, Rating, PriceRange, Location, Sublocation FROM Restaurant WHERE Sublocation = '%s'"%(location)
            sublocation_view = getData(sublocation_view_query)
            dispatcher.utter_message(text="یہ جگہ کس ایریا میں ہے")
        else:
            flag = 0


            if cuisine is None and price is None:

                json_string = json.dumps(location_query_1)
                print(isinstance(json_string, str))
                print("Check here")

                list_a=json_string.split(',')
                remove=["'",'"','[',']']

                for i in remove:
                    list_a=[s.replace(i, '') for s in list_a]


                dispatcher.utter_message(text="Restaurants in Location only: ")
                dispatcher.utter_message(list_a)

---

如果数据以垂直列表格式（新行缩进）显示，并且没有括号和引号，我应该怎么做？谢谢

首先，您是否尝试过将数据读入pandas对象？我已经使用sqlite数据库完成了一些程序，这对我很有用：

df = pd.read_sql_query("SELECT * FROM {}".format(self.tablename), conn)

现在转到字符串格式部分：

# this code should do the work for you
# first of all we have our string a like yours
a="[['hallo'],['welt'],['kannst'],['du'],['mich'],['hoeren?']]"
# now we split the string into a list on every ,
list_a=a.split(',')
# this is our list with chars we want to remove
remove=["'",'"','[',']']

# now we replace all elements step by step with nothing
for i in remove:
    list_a=[s.replace(i, '') for s in list_a]

print(list_a)
for z in list_a:
    print(z)

然后输出为：

['hallo', 'welt', 'kannst', 'du', 'mich', 'hoeren?']
hallo
welt
kannst
du
mich
hoeren?

---

希望我能帮忙。

非常感谢！我也会尝试熊猫的方式。是的，有了熊猫会更容易。没有问题每次我试着运行这个：>>list_a=json_string.split（'，'）它会给我一个错误：对于text.strip（）.split（“\n\n”）：AttributeError:'list'对象没有属性'strip'，好奇怪，你可以分享你的完整代码吗。也许我明白会发生什么？也许在GitHub上或者类似的东西上。好吧，我觉得你的字符串有点不对劲。你能把这个字符串打印出来，然后再分享一下吗？或者尝试添加list_a=str（json_string）.split（'，'）。