Python 我需要输入一个数字。如果否,则显示“否”;请输入数字“;然后再次请求输入
这就是我想要的,但是对于整数。我不允许使用Python 我需要输入一个数字。如果否,则显示“否”;请输入数字“;然后再次请求输入,python,python-3.x,input,integer,Python,Python 3.x,Input,Integer,这就是我想要的,但是对于整数。我不允许使用中断或继续退出循环 # basically I need this, but with an int(input('please enter a number')) ask = input('Would you like to play Steal or Deal [y|n]? ') while ask not in ('y', 'n'): print ("Please enter either 'y' or 'n'"
中断
或继续
退出循环
# basically I need this, but with an int(input('please enter a number'))
ask = input('Would you like to play Steal or Deal [y|n]? ')
while ask not in ('y', 'n'):
print ("Please enter either 'y' or 'n'")
print('')
ask = input('Would you like to play Steal or Deal [y|n]? ')
您可以尝试将字符串转换为int并捕获异常:
def is_number(s):
try:
int(s)
return True
except ValueError:
return False
ask = input('please enter a number: ')
while not is_number(ask):
print ("no, a number!")
print('')
ask = input('please enter a number: ')