Python 处理来自模块的异常

我正在尝试使用我从中导入thetvdb的模块。我设法将模块导入到我的代码中，但我试图从模块中获取错误以了解结果。节目未找到、剧集未找到等，我无法在不破坏脚本的情况下成功做到这一点

这是我当前的代码：

#!/usr/bin/env python3
from tvdb_api import tvdb_api
t = tvdb_api.Tvdb()

show_name = raw_input("What is the tv show? ")
season_num = int(raw_input("What is the season number? "))
episode_num = int(raw_input("What is the episode number? "))
try:
        episode = t[show_name][season_num][episode_num] # get season 1, episode 3 of show
        print episode['episodename'] # Print episode name
except tvdb_api.tvdb_exception:
        print("error")

我想要的不仅仅是我正在打印的东西。我尝试过返回，但python告诉我它不在函数中。我认为让我不快的是错误类是空的

以下是tvdbapi.py文件中异常类的片段：

## Exceptions

class tvdb_exception(Exception):
    """Any exception generated by tvdb_api
    """
    pass

class tvdb_error(tvdb_exception):
    """An error with thetvdb.com (Cannot connect, for example)
    """
    pass

class tvdb_userabort(tvdb_exception):
    """User aborted the interactive selection (via
    the q command, ^c etc)
    """
    pass

class tvdb_notauthorized(tvdb_exception):
    """An authorization error with thetvdb.com
    """
    pass

class tvdb_shownotfound(tvdb_exception):
    """Show cannot be found on thetvdb.com (non-existant show)
    """
    pass

class tvdb_seasonnotfound(tvdb_exception):
    """Season cannot be found on thetvdb.com
    """
    pass

class tvdb_episodenotfound(tvdb_exception):
    """Episode cannot be found on thetvdb.com
    """
    pass

class tvdb_resourcenotfound(tvdb_exception):
    """Resource cannot be found on thetvdb.com
    """
    pass

---

您可能还需要打印异常：

尝试： ... 除了tvdb_api.tvdb_例外，作为exc： 打印错误：，exc

---

天哪。我曾经试图打印tvdb_api.tvdb_异常。我不知道你可以像exc那样做，然后打印出来…它成功了！我希望脚本有错误代码而不是文本，但是谢谢！几个小时来我一直在读这本书，还一直在敲我的脑袋！可能重复的