Python字典和

嗨，伙计们，我有一个问题，如何在字典里对相同的IP地址求和。 我有一个输入文件，该文件如下所示：

IP           , Byte
10.180.176.61,3669
10.164.134.193,882
10.164.132.209,4168
10.120.81.141,4297
10.180.176.61,100

#!/usr/bin/python
# -*- coding: utf-8 -*-

import re,sys, os
from collections import defaultdict

f     = open('splited/small_file_1000000.csv','r')
o     = open('gotovo1.csv','w')

list_of_dictionaries = {}

for line in f:
    if re.search(r'\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}.*',line):
        line_ip = re.findall(r'\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}',line)[0]
        line_by = re.findall(r'\,\d+',line)[0]
        line_b = re.sub(r'\,','',line_by)

        list_of_dictionaries['IP']  = line_ip
        list_of_dictionaries['VAL'] = int(line_b)


c = defaultdict(int)
for d in list_of_dictionaries:
    c[d['IP']] += d['VAL']

print c

我的动作是打开那个文件，用逗号后的数字解析IP地址，这样我就可以对一个IP地址的所有字节求和。所以我可以得到如下结果：

IP 10.180.176.61 , 37669

我的代码如下所示：

IP           , Byte
10.180.176.61,3669
10.164.134.193,882
10.164.132.209,4168
10.120.81.141,4297
10.180.176.61,100

#!/usr/bin/python
# -*- coding: utf-8 -*-

import re,sys, os
from collections import defaultdict

f     = open('splited/small_file_1000000.csv','r')
o     = open('gotovo1.csv','w')

list_of_dictionaries = {}

for line in f:
    if re.search(r'\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}.*',line):
        line_ip = re.findall(r'\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}',line)[0]
        line_by = re.findall(r'\,\d+',line)[0]
        line_b = re.sub(r'\,','',line_by)

        list_of_dictionaries['IP']  = line_ip
        list_of_dictionaries['VAL'] = int(line_b)


c = defaultdict(int)
for d in list_of_dictionaries:
    c[d['IP']] += d['VAL']

print c

任何想法都很好

使用模块读取您的文件并汇总每个IP地址的总数：

from collections import Counter
import csv


def read_csv(fn):
    with open(fn, 'r') as csvfile:
        reader = csv.reader(csvfile, delimiter=',')
        reader.next()    # Skip header
        for row in reader:
            ip, bytes = row
            yield ip, int(bytes)


totals = Counter()
for ip, bytes in read_csv('data.txt'):
    totals[ip] += bytes

print totals

输出：

Counter({'10.120.81.141': 4297, '10.164.132.209': 4168, '10.180.176.61': 3769, '10.164.134.193': 882})

---

如果您的文件看起来像您提供的示例，则不需要正则表达式来解析它。只需使用逗号拆分行：