Python 如何从一个数字中连续减法

初学者python用户在这里。我正在为rpg中的基本攻击编写一些代码，看起来是这样的：

随机输入 职业攻击： 健康=300 对于范围1中的i： 如果random.uniform0，10使用while循环

while health > 0:
    if (random.uniform(0, 10)) <= int(8.2):
        health = health - 50
        print("Your attack hit.\n" + "The monster's health is at " + str(health))
    else:
         print("Your attack missed.\n" + "The monster's health is at " + str(health))

您可以使用while循环-在本例中，它将运行直到满足条件，直到运行状况为0：

while health > 0:
    if (random.uniform(0, 10)) <= int(8.2):
            health = health - 50
            print("Your attack hit.\n" + "The monster's health is at " + str(health))
        else:
            print("Your attack missed.\n" + "The monster's health is at " + str(health))

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您的循环只执行一次

for i in range(1):

如果希望它一直运行到运行状况为0，则需要一个while循环：

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最好使用函数，而不是类，并且可以使用while循环继续攻击小于0的运行状况

import random
def attack():
    health = 300
    while health > 0:
        if (random.uniform(0, 10)) <= int(8.2):
             health -= 50
             print("Your attack hit.\n" + "The monster's health is at " + str(health))
        else:
             print("Your attack missed.\n" + "The monster's health is at " + str(health))
attack()

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若要继续，您必须使用比range1更大的值-即range5，命中5次-或者，如果为True，则使用break退出无限循环。或者当生命值>0时：而不是循环。或者当生命值>0时：继续攻击直到你获胜。生命值应该是怪物对象的属性。换句话说，你应该在你的monster类中暗示这一点。你的代码将在没有类攻击的情况下同等工作：line。您可能希望从示例代码中删除，以避免混淆。固定程序的预期输出是什么？

import random
def attack():
    health = 300
    while health > 0:
        if (random.uniform(0, 10)) <= int(8.2):
             health -= 50
             print("Your attack hit.\n" + "The monster's health is at " + str(health))
        else:
             print("Your attack missed.\n" + "The monster's health is at " + str(health))
attack()