Python 将项目列表拆分为一个列表

我有一个项目清单：

['1', 'Date stored: 2019-02-01; ', 'Author name: l; ', 'Book title: lll; ', 'Quantity: 1; ', 'Price: 2. ', '', '2', 'Date stored: 2019-01-02; ', 'Author name: ghjk; ', 'Book title: okj; ', 'Quantity: 5; ', 'Price: 4. ', '', '4', 'Date stored: 2019-01-02; ', 'Author name: hello; ', 'Book title: hekie; ', 'Quantity: 1; ', 'Price: 2. ', '', '1', 'Date stored: 2019-02-01; ', 'Author name: k; ', 'Book title: k; ', 'Quantity: 4; ', 'Price: 1. ', '', '1', 'Date stored: 2019-01-01; ', 'Author name: o; ', 'Book title: b; ', 'Quantity: 4; ', 'Price: 8; ', '', '5', 'Date stored: 2019-02-01; ', 'Author name: dfgh; ', 'Book title: iuhg; ', 'Quantity: 8; ', 'Price: 4. ', '']

我想把它放入列表列表中，所以我想在

'

部分对它进行切片，使其看起来像这样：

[['1', 'Date stored: 2019-02-01; ', 'Author name: l; ', 'Book title: lll; ', 'Quantity: 1; ', 'Price: 2. '], ['2', 'Date stored: 2019-01-02; ', 'Author name: ghjk; ', 'Book title: okj; ', 'Quantity: 5; ', 'Price: 4. '], ... ]

as_string = ' '.join(lst).split(' ')
as_string_list = [i.strip.split(' ') for i in as_string]
print(as_string_list)

我现在有这个代码：

lst = []
lst1 = []


for line in mainFileDelete:
    stripped = line.strip("\n")
    lst.append(stripped)
print(lst)


for item in lst:
    splited = lst.index('')
    l2 = lst[:splited]
    lst1.append(l2)
print(lst1)

第一个for循环将所有项放入一个列表中，如示例所示，但第二个for循环生成一个列表列表，但仅使用第一行，如下所示：

[['1', 'Date stored: 2019-02-01; ', 'Author name: l; ', 'Book title: lll; ', 'Quantity: 1; ', 'Price: 2. '], ['1', 'Date stored: 2019-02-01; ', 'Author name: l; ', 'Book title: lll; ', 'Quantity: 1; ', 'Price: 2. '], ['1', 'Date stored: 2019-02-01; ', 'Author name: l; ', 'Book title: lll; ', 'Quantity: 1; ', 'Price: 2. '], ['1', 'Date stored: 2019-02-01; ', 'Author name: l; ', 'Book title: lll; ', 'Quantity: 1; ', 'Price: 2. '], ['1', 'Date stored: 2019-02-01; ', 'Author name: l; ', 'Book title: lll; ', 'Quantity: 1; ', 'Price: 2. '], ['1', 'Date stored: 2019-02-01; ', 'Author name: l; ', 'Book title: lll; ', 'Quantity: 1; ', 'Price: 2. '], ... ] 

我不知道如何使它使

lst

从第一个循环变成一个列表列表。 我也试过这样做：

[['1', 'Date stored: 2019-02-01; ', 'Author name: l; ', 'Book title: lll; ', 'Quantity: 1; ', 'Price: 2. '], ['2', 'Date stored: 2019-01-02; ', 'Author name: ghjk; ', 'Book title: okj; ', 'Quantity: 5; ', 'Price: 4. '], ... ]

as_string = ' '.join(lst).split(' ')
as_string_list = [i.strip.split(' ') for i in as_string]
print(as_string_list)

---

但是我的

lst

有

'

我想拆分的地方，所以它不起作用

手动拆分列表的通用算法：

当我们得到一个非

'

时，我们将一个元素添加到当前子列表中，如果我们点击

'

，我们将启动另一个子列表

result=[]
sublist=[]
for elem in lst:
    if elem: #or: if elem=='':
        sublist.append(elem)
    else:
        result.append(sublist)
        sublist=[]
if sublist: #in case your list wouldn't end with 
    result.append(sublist)
#del sublist
print(result)

结果:

>>> print(result)
[['1', 'Date stored: 2019-02-01; ', 'Author name: l; ', 'Book title: lll; ', 'Quantity: 1; ', 'Price: 2. '], ['2', 'Date stored: 2019-01-02; ', 'Author name: ghjk; ', 'Book title: okj; ', 'Quantity: 5; ', 'Price: 4. '], ['4', 'Date stored: 2019-01-02; ', 'Author name: hello; ', 'Book title: hekie; ', 'Quantity: 1; ', 'Price: 2. '], ['1', 'Date stored: 2019-02-01; ', 'Author name: k; ', 'Book title: k; ', 'Quantity: 4; ', 'Price: 1. '], ['1', 'Date stored: 2019-01-01; ', 'Author name: o; ', 'Book title: b; ', 'Quantity: 4; ', 'Price: 8; '], ['5', 'Date stored: 2019-02-01; ', 'Author name: dfgh; ', 'Book title: iuhg; ', 'Quantity: 8; ', 'Price: 4. ']]

---

您可以使用上面链接中提供的相同函数，并使用

tokenize\u list（数组，sep=''）

。很好的一个shaik，只是sep应该是

sep=''

。非常感谢。