Python 如何将字符串中每个单词的第一个字母大写？
…在这里做点什么Python 如何将字符串中每个单词的第一个字母大写？,python,capitalization,capitalize,Python,Capitalization,Capitalize,…在这里做点什么 s应为： s = 'the brown fox' 最简单的方法是什么？字符串方法（ASCII或Unicode都可以）执行以下操作： 'The Brown Fox' 但是，请注意文档中提到的带有内嵌撇号的字符串 该算法使用一个简单的独立于语言的定义，将一个单词定义为一组连续的字母。这个定义在许多语境中都适用，但它意味着缩略语和所有格中的撇号形成了单词边界，这可能不是期望的结果： >>> "hello world".title() 'Hel
ss = 'the brown fox'
'The Brown Fox'
>>> "hello world".title()
'Hello World'
>>> u"hello world".title()
u'Hello World'
就因为这类事情对我来说很有趣，这里还有两个解决方案 拆分为单词，在拆分的组中为每个单词加上大写字母，然后重新加入。这将改变将单词分隔为单个空格的空白，无论它是什么
>>> "they're bill's friends from the UK".title()
"They'Re Bill'S Friends From The Uk"
编辑：我不记得我写上述代码时的想法，但是没有必要建立一个明确的列表；我们可以使用生成器表达式以惰性方式执行此操作。因此，这里有一个更好的解决方案：
s = 'the brown fox'
lst = [word[0].upper() + word[1:] for word in s.split()]
s = " ".join(lst)
使用正则表达式匹配字符串的开头，或空格分隔单词，再加上一个非空格字符；使用括号标记“匹配组”。编写一个函数，该函数接受匹配对象，并以大写形式返回空白匹配组和非空白字符匹配组。然后使用
re.sub（）s = 'the brown fox'
s = ' '.join(word[0].upper() + word[1:] for word in s.split())
re.sub（）re.sub（）import re
s = 'the brown fox'
def repl_func(m):
"""process regular expression match groups for word upper-casing problem"""
return m.group(1) + m.group(2).upper()
s = re.sub("(^|\s)(\S)", repl_func, s)
>>> re.sub("(^|\s)(\S)", repl_func, s)
"They're Bill's Friends From The UK"
>>> ' '.join([s[0].upper() + s[1:] for s in "they're bill's friends from the UK".split(' ')])
"They're Bill's Friends From The UK"
string = "the brown fox"
string[0].upper()+string[1:]
@jibberia anwser的复制粘贴就绪版本：
input = "they're bill's friends from the UK"
words = input.split(' ')
capitalized_words = []
for word in words:
title_case_word = word[0].upper() + word[1:]
capitalized_words.append(title_case_word)
output = ' '.join(capitalized_words)
import string
string.capwords("they're bill's friends from the UK")
>>>"They're Bill's Friends From The Uk"
def capitalize(line):
return ' '.join(s[:1].upper() + s[1:] for s in line.split(' '))
我很喜欢这个答案：
@jibberia anwser的复制粘贴就绪版本：
input = "they're bill's friends from the UK"
words = input.split(' ')
capitalized_words = []
for word in words:
title_case_word = word[0].upper() + word[1:]
capitalized_words.append(title_case_word)
output = ' '.join(capitalized_words)
import string
string.capwords("they're bill's friends from the UK")
>>>"They're Bill's Friends From The Uk"
return ' '.join([s[0].upper() + s[1:] for s in line.split(' ') if len(s)>0])
str = "this is string example.... wow!!!";
print "str.title() : ", str.title();
正如Mark指出的，您应该使用： 但是，如果您希望在Django模板中使用大写字母，可以使用以下方法：
"MyAwesomeString".title()
string = 1 w 2 r 3g
{{ "MyAwesomeString"|title }}
当解决方案简单且安全时，为什么要用连接和for循环使生活复杂化 只要这样做：
{{ myvar|title }}
建议的方法str.title（）并不适用于所有情况。 例如：
>>> ' '.join([s[0].upper() + s[1:] for s in "they're bill's friends from the UK".split(' ')])
"They're Bill's Friends From The UK"
string = "the brown fox"
string[0].upper()+string[1:]
“ab3c”string = "a b 3c"
string.title()
> "A B 3C"
这里总结了各种方法，它们适用于所有这些输入：
def capitalize_words(string):
words = string.split(" ") # just change the split(" ") method
return ' '.join([word.capitalize() for word in words])
capitalize_words(string)
>'A B 3c'
"" => ""
"a b c" => "A B C"
"foO baR" => "FoO BaR"
"foo bar" => "Foo Bar"
"foo's bar" => "Foo's Bar"
"foo's1bar" => "Foo's1bar"
"foo 1bar" => "Foo 1bar"
# Be careful with multiple spaces, and empty strings
# for empty words w[0] would cause an index error,
# but with w[:1] we get an empty string as desired
def cap_sentence(s):
return ' '.join(w[:1].upper() + w[1:] for w in s.split(' '))
# Iterate through each of the characters in the string and capitalize
# the first char and any char after a blank space
from itertools import chain
def cap_sentence(s):
return ''.join( (c.upper() if prev == ' ' else c) for c, prev in zip(s, chain(' ', s)) )
现在，这些是一些已发布的其他答案，以及如果我们使用单词的定义作为句子的开头或空格后的任何内容，则这些答案和输入不符合预期：
# match the beginning of the string or a space, followed by a non-space
import re
def cap_sentence(s):
return re.sub("(^|\s)(\S)", lambda m: m.group(1) + m.group(2).upper(), s)
将“”用于拆分将修复第二个输出，但capwords（）对于第一个输出仍然不起作用
return ' '.join(w.capitalize() for w in s.split())
# or
import string
return string.capwords(s)
# Undesired outputs:
"foO baR" => "Foo Bar"
"foo bar" => "Foo Bar"
注意多个空格
return ' '.join(w.capitalize() for w in s.split(' '))
# or
import string
return string.capwords(s, ' ')
# Undesired outputs:
"foO baR" => "Foo Bar"
如果访问[1:]，空字符串将引发错误。因此，我将使用：
return ' '.join(w[0].upper() + w[1:] for w in s.split())
# Undesired outputs:
"foo bar" => "Foo Bar"
仅大写第一个字母。不要忽略保留空白。如果您想处理
'fred flinstone''fred flinstone''fred flinstone'def my_uppercase(title):
if not title:
return ''
return title[0].upper() + title[1:]
如果你想要第一个字母： “你好，世界”。大写（） “你好，世界” 但要大写每个单词：
>“你好，世界”。title（）
“你好，世界”
虽然所有的答案都是令人满意的，但我会尽量把这两个额外的案例和之前的案例都包括在内 如果空间不一致，并且您希望保持不变 如果所有字符串不是从字母表开始的 在这里，您可以使用：
"MyAwesomeString".title()
string = 1 w 2 r 3g
def solve(s):
a = s.split(' ')
for i in range(len(a)):
a[i]= a[i].capitalize()
return ' '.join(a)
一个适用于Python 3的快速函数
output = Hello World I Am Here
output = 1 W 2 R 3g
使用非均匀空格将字符串大写 我想在@Amit Gupta的非均匀空间点上添加以下内容： 从原来的问题开始，我们想将字符串
s='thebrownfox's='thebrownfox'Python 3.6.9 (default, Nov 7 2019, 10:44:02)
[GCC 8.3.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> capitalizeFirtChar = lambda s: s[:1].upper() + s[1:]
>>> print(capitalizeFirtChar('помните своих Предковъ. Сражайся за Правду и Справедливость!'))
Помните своих Предковъ. Сражайся за Правду и Справедливость!
>>> print(capitalizeFirtChar('хай живе вільна Україна! Хай живе Любовь поміж нас.'))
Хай живе вільна Україна! Хай живе Любовь поміж нас.
>>> print(capitalizeFirtChar('faith and Labour make Dreams come true.'))
Faith and Labour make Dreams come true.
对于您的问题，最简单的解决方案在我的案例中有效：
def solve(s):
# If you want to maintain the spaces in the string, s = 'the brown fox'
# Use s.split(' ') instead of s.split().
# s.split() returns ['the', 'brown', 'fox']
# while s.split(' ') returns ['the', 'brown', '', '', '', '', '', 'fox']
capitalized_word_list = [word.capitalize() for word in s.split(' ')]
return ' '.join(capitalized_word_list)
Python 3.6.9 (default, Nov 7 2019, 10:44:02)
[GCC 8.3.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> capitalizeFirtChar = lambda s: s[:1].upper() + s[1:]
>>> print(capitalizeFirtChar('помните своих Предковъ. Сражайся за Правду и Справедливость!'))
Помните своих Предковъ. Сражайся за Правду и Справедливость!
>>> print(capitalizeFirtChar('хай живе вільна Україна! Хай живе Любовь поміж нас.'))
Хай живе вільна Україна! Хай живе Любовь поміж нас.
>>> print(capitalizeFirtChar('faith and Labour make Dreams come true.'))
Faith and Labour make Dreams come true.
def solve(s):
# If you want to maintain the spaces in the string, s = 'the brown fox'
# Use s.split(' ') instead of s.split().
# s.split() returns ['the', 'brown', 'fox']
# while s.split(' ') returns ['the', 'brown', '', '', '', '', '', 'fox']
capitalized_word_list = [word.capitalize() for word in s.split(' ')]
return ' '.join(capitalized_word_list)
import string
def solve(s):
return string.capwords(s,' ')
s=input()
res=solve(s)
print(res)
k=y.split()
for i in k:
y=y.replace(i,i.capitalize())
return y