Python 在QWidget中实现keyPressEvent
我有一个带有“继续”按钮的QDialog窗口。“继续”按钮是默认按钮,因为每当我按下enter键时,都会按下“继续”按钮。我发现了一些奇怪的事情:当我按三次回车键时,继续按钮按了三次。然而,当我第四次按下它时,整个窗口关闭。我在关闭窗口的“继续”按钮的正下方有一个“取消”按钮,但我没有将“取消”按钮设置为默认按钮或其他任何按钮 我想覆盖Python 在QWidget中实现keyPressEvent,python,event-handling,pyqt,keypress,Python,Event Handling,Pyqt,Keypress,我有一个带有“继续”按钮的QDialog窗口。“继续”按钮是默认按钮,因为每当我按下enter键时,都会按下“继续”按钮。我发现了一些奇怪的事情:当我按三次回车键时,继续按钮按了三次。然而,当我第四次按下它时,整个窗口关闭。我在关闭窗口的“继续”按钮的正下方有一个“取消”按钮,但我没有将“取消”按钮设置为默认按钮或其他任何按钮 我想覆盖keyPressEvent,这样每当我在窗口中时,enter按钮将始终连接到continue按钮 这就是我现在拥有的: class ManualBalanceUI
keyPressEvent
,这样每当我在窗口中时,enter按钮将始终连接到continue按钮
这就是我现在拥有的:
class ManualBalanceUI(QtGui.QWidget):
keyPressed = QtCore.pyqtSignal()
def __init__(self, cls):
super(QtGui.QWidget, self).__init__()
self.window = QtGui.QDialog(None, QtCore.Qt.WindowSystemMenuHint)
self.ui = uic.loadUi('ManualBalanceUI.ui', self.window)
self.keyPressed.connect(self.on_key)
def keyPressEvent(self, event):
super(ManualBalanceUI, self).keyPressEvent(event)
self.keyPressed.emit(event)
def on_key(self, event):
if event.key() == QtCore.Qt.Key_Enter and self.ui.continueButton.isEnabled():
self.proceed() # this is called whenever the continue button is pressed
elif event.key() == QtCore.Qt.Key_Q:
self.window.close() # a test I implemented to see if pressing 'Q' would close the window
def proceed(self):
...
...
然而,现在看来这并没有起到任何作用。按“Q”键不会关闭窗口,而且我也无法真正判断“回车”键是否起作用
我事先看了这个问题:
我还查看了SourceForge的所有文档。任何帮助都将不胜感激 你可以用两种方法,一种是不做任何花哨的工作,简单地重新实现keyPressevent。像这样
from PyQt4 import QtCore, QtGui
import sys
class Example(QtGui.QWidget):
def __init__(self):
super(Example, self).__init__()
self.setGeometry(300, 300, 250, 150)
self.show()
def keyPressEvent(self, event):
if event.key() == QtCore.Qt.Key_Q:
print "Killing"
self.deleteLater()
elif event.key() == QtCore.Qt.Key_Enter:
self.proceed()
event.accept()
def proceed(self):
print "Call Enter Key"
def main():
app = QtGui.QApplication(sys.argv)
ex = Example()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
或者,当您尝试使用信号时,在您的情况下,您缺少正确实现此信号的地方,这里是更新版本
class Example(QtGui.QWidget):
keyPressed = QtCore.pyqtSignal(QtCore.QEvent)
def __init__(self):
super(Example, self).__init__()
self.setGeometry(300, 300, 250, 150)
self.show()
self.keyPressed.connect(self.on_key)
def keyPressEvent(self, event):
super(Example, self).keyPressEvent(event)
self.keyPressed.emit(event)
def on_key(self, event):
if event.key() == QtCore.Qt.Key_Enter and self.ui.continueButton.isEnabled():
self.proceed() # this is called whenever the continue button is pressed
elif event.key() == QtCore.Qt.Key_Q:
print "Killing"
self.deleteLater() # a test I implemented to see if pressing 'Q' would close the window
def proceed(self):
print "Call Enter Key"
def main():
app = QtGui.QApplication(sys.argv)
ex = Example()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
对于阿卡扬的回答,我成功地使用了密码。 它可能是回车键和回车键。 尝试按Enter键和Return键。它们在我的键盘上是不同的
QtCore.QObject.connect(self.ui.search_box, QtCore.SIGNAL("textChanged()"), self.fucn1)
每当在搜索框
中更改文本时,就会调用函数fucn1
。
适用于pyqt4如果您在2019年看到这一点,并且如果Achayan的方法不适用于您,请检查以下几点: 1) 按键事件是否在主窗口或主窗口小部件的子窗口中被覆盖?子函数将重写父函数上的方法(至少在使用带有setCentralWidget的QMainWindow时)。如果是这种情况,那么信号可能不会像您预期的那样发出 2) 您是否有一个与QWidget不同的小部件来处理关键输入?例如,如果焦点位于QTextEdit对象中,则按键输入将不会发送到keyPressEvent。将焦点转移到另一个 例如,观察以下各项的输出:
class myDialog(QtWidgets.QDialog):
keyPressed = QtCore.pyqtSignal(QtCore.QEvent)
def __init__(self, parent=None):
super(myDialog, self).__init__(parent)
self.keyPressed.connect(self.on_key)
leftGroupBox = QtWidgets.QGroupBox('A Group Label')
text = QtWidgets.QTextEdit('Enter some text')
layout = QtWidgets.QVBoxLayout()
layout.addWidget(text)
leftGroupBox.setLayout(layout)
rightGroupBox = QtWidgets.QGroupBox('Label Options')
label1 = QtWidgets.QCheckBox('ahu')
layout = QtWidgets.QVBoxLayout()
layout.addWidget(label1)
rightGroupBox.setLayout(layout)
# Create the main layout
mainLayout = QtWidgets.QGridLayout()
mainLayout.addWidget(leftGroupBox)
mainLayout.addWidget(rightGroupBox)
self.setLayout(mainLayout)
def keyPressEvent(self, event):
# keyPressEvent defined in child
print('pressed from myDialog: ', event.key())
# self.keyPressed.emit(event) # Emit is hidden in child
def on_key(self, event):
print('event received @ myDialog')
if event.key() == QtCore.Qt.Key_0:
print(0)
class MainWindow(QtWidgets.QMainWindow):
keyPressed = QtCore.pyqtSignal(QtCore.QEvent)
def __init__(self):
super(MainWindow, self).__init__()
self.keyPressed.connect(self.on_key)
self.setCentralWidget(myDialog())
self.show()
def keyPressEvent(self, event):
super(MainWindow, self).keyPressEvent(event)
print('pressed from MainWindow: ', event.key())
self.keyPressed.emit(event)
def on_key(self, event):
print('event received @ MainWindow')
if event.key() == QtCore.Qt.Key_0:
print(0)
if __name__ == '__main__':
ex = MainWindow()
谢谢你的回答!我尝试了两种方法,不幸的是它们都不适合我。我会继续玩弄它,我会评论一些应该有效的东西,这是我能提供的最简单的例子。。祝你好运:)
Output @ console : (no event is received @myDialog OR MainWindow)
pressed from myDialog: 48