Python 为什么可以'；在向api/url发出请求后是否打印响应？

我刚刚通过检查xhr找到了bestbuyCA api

 aboveurl = 'https://www.bestbuy.ca/ecomm-api/availability/products?accept=application%2Fvnd.bestbuy.simpleproduct.v1%2Bjson&accept-language=en-CA&skus=14962185'

我试过：：

  response= requests.get(aboveurl)
  print(response.text)

//

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当我在vsc中运行我的代码时，它会启动并保持运行，但不会显示任何内容。

您必须向请求添加一个标题才能获得请求结果：

import requests
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/56.0.2924.76 Safari/537.36', "Upgrade-Insecure-Requests": "1","DNT": "1","Accept": "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8","Accept-Language": "en-US,en;q=0.5","Accept-Encoding": "gzip, deflate"}
aboveurl = "https://www.bestbuy.ca/ecomm-api/availability/products?accept=application%2Fvnd.bestbuy.simpleproduct.v1%2Bjson&accept-language=en-CA&skus=14962185"
html = requests.get(aboveurl,headers=headers)
print(f'requrest code: {html.status_code}\n request text: {html.text}')

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只是快速查看一下，您的URL看起来不像URL=''上面的字符串。很抱歉，这是一个输入错误。您可能需要在请求中添加HTTP头。谢谢，有没有我可以阅读的文档可以帮助我理解这样的事情，比如为什么它需要一个标题，以及当我对回复进行查询时api在寻找什么，有没有我可以阅读的推荐文档来解释这一点？是的，你可以阅读官方的感谢，很抱歉再次打扰你。我试图用html.json将“html”转换为json，但它给了我一个错误代码“json.decoder.jsondecoderror:意外的UTF-8 BOM（使用UTF-8-sig解码）”。有没有办法将响应“html”转换为json？“html”是，它不应该包含json吗？嗨，我可以通过使用“decoded_data=html.text.encode（）.decode（'utf-8-sig'）data=json.loads（decoded_data）”来解决它，这很好^^

import requests
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/56.0.2924.76 Safari/537.36', "Upgrade-Insecure-Requests": "1","DNT": "1","Accept": "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8","Accept-Language": "en-US,en;q=0.5","Accept-Encoding": "gzip, deflate"}
aboveurl = "https://www.bestbuy.ca/ecomm-api/availability/products?accept=application%2Fvnd.bestbuy.simpleproduct.v1%2Bjson&accept-language=en-CA&skus=14962185"
html = requests.get(aboveurl,headers=headers)
print(f'requrest code: {html.status_code}\n request text: {html.text}')