Python Django DeleteView不带确认模板
我在模板中使用Django DeleteView，并创建了一个url和视图。Python Django DeleteView不带确认模板,python,django,Python,Django,我在模板中使用Django DeleteView，并创建了一个url和视图。 是否可以跳过加载_确认_删除模板的过程并立即发布删除操作。是的，只需更改下一个参数。在返回响应中，确保传入的字典具有以下内容：{'next'：'/}/'}，确保在添加next参数之前提交更改。您可能需要更改视图的get和post功能。DeleteView响应post和get请求，get请求显示确认模板，而post删除实例 您可以发送POST请求，无需确认，格式如下： <form method="POST" act
是否可以跳过加载_确认_删除模板的过程并立即发布删除操作。是的，只需更改下一个参数。在返回响应中，确保传入的字典具有以下内容：
{'next'：'/}/'}nextgetpostDeleteViewpostgetgetpostPOST<form method="POST" action="{% url "your_delete_url_name" %}">
{% csrf_token %}<input type="submit" value="DELETE">
</form>
path('posts/delete/<int:pk>/', PostDeleteView.as_view(), name='post_delete'),
或者您可以在
DeleteViewget（）class YourDeleteView(DeleteView):
model = YourModel
success_url = '<success_url>'
def get(self, request, *args, **kwargs):
return self.post(request, *args, **kwargs)
class YourDeleteView（DeleteView）：
模型=你的模型
成功\u url=“”
def get（自我、请求、*args、**kwargs）：
返回self.post（请求，*args，**kwargs）
但是要小心，确保这不会影响其他功能。您所要做的就是覆盖删除视图的
get\u success\u urlclass YourView(DeleteView):
model = YourModel
def get_success_url(self):
return reverse('your_redirect_view')
或者，您只能通过将请求直接路由到类的
deletedeletefrom django.views.generic import DeleteView
from django.http import HttpResponseForbidden
class PostDeleteView(DeleteView):
model = Post
http_method_names = ['delete']
def dispatch(self, request, *args, **kwargs):
# safety checks go here ex: is user allowed to delete?
if request.user.username != kwargs['username']:
return HttpResponseForbidden()
else:
handler = getattr(self, 'delete')
return handler(request, *args, **kwargs)
def get_success_url(self):
username = self.kwargs.get('username')
success_url = str(reverse_lazy('post:user_home', kwargs={'username': username}))
return success_url
<form method="POST" action="{% url "your_delete_url_name" %}">
{% csrf_token %}<input type="submit" value="DELETE">
</form>
path('posts/delete/<int:pk>/', PostDeleteView.as_view(), name='post_delete'),
postdeletedeletepk\u url\u kwarg='pk'postget（）post（）