如何使用python的re模块从以下字符串中获取键值样式信息

我们有这样一个字符串：

2016-11-10 00:00:44,766 INFO [com.server.log.Log] - <Login Success. userInfo:  userID = 140803;appID = 3;channelID = 309;channelUserID = 76ab5a49ea40477f9623074d0d5e0227;userName = 1477806062675.ios.test;channelUserName = l379192229;createTime = 2016-10-30 13:41:02.0;loginTime = 1478707244762;userIP = 61.158.146.157;IMEI = FB7FE841-9E54-4421-86E0-1ED625068C57;newUser = false>

现在我想使用python的re模块从字符串中提取键值信息

因此，它应该是一个dict:{'userID'：140803'channelid'：309…}

给你：

import re

string = """
2016-11-10 00:00:44,766 INFO [com.server.log.Log] - <Login Success. userInfo:  userID = 140803;appID = 3;channelID = 309;channelUserID = 76ab5a49ea40477f9623074d0d5e0227;userName = 1477806062675.ios.test;channelUserName = l379192229;createTime = 2016-10-30 13:41:02.0;loginTime = 1478707244762;userIP = 61.158.146.157;IMEI = FB7FE841-9E54-4421-86E0-1ED625068C57;newUser = false>
"""

rx = re.compile(r'(?P<key>\w+)[ ]*=[ ]*(?P<value>[^;]+)')

result = dict()
for m in rx.finditer(string):
    result[m.group('key')] = m.group('value')
print(result)
# {'userName': '1477806062675.ios.test', 'channelUserName': 'l379192229', 'channelID': '309', 'userID': '140803', 'loginTime': '1478707244762', 'IMEI': 'FB7FE841-9E54-4421-86E0-1ED625068C57', 'appID': '3', 'userIP': '61.158.146.157', 'channelUserID': '76ab5a49ea40477f9623074d0d5e0227', 'newUser': 'false>\n', 'createTime': '2016-10-30 13:41:02.0'}

请参阅。

给您：

import re

string = """
2016-11-10 00:00:44,766 INFO [com.server.log.Log] - <Login Success. userInfo:  userID = 140803;appID = 3;channelID = 309;channelUserID = 76ab5a49ea40477f9623074d0d5e0227;userName = 1477806062675.ios.test;channelUserName = l379192229;createTime = 2016-10-30 13:41:02.0;loginTime = 1478707244762;userIP = 61.158.146.157;IMEI = FB7FE841-9E54-4421-86E0-1ED625068C57;newUser = false>
"""

rx = re.compile(r'(?P<key>\w+)[ ]*=[ ]*(?P<value>[^;]+)')

result = dict()
for m in rx.finditer(string):
    result[m.group('key')] = m.group('value')
print(result)
# {'userName': '1477806062675.ios.test', 'channelUserName': 'l379192229', 'channelID': '309', 'userID': '140803', 'loginTime': '1478707244762', 'IMEI': 'FB7FE841-9E54-4421-86E0-1ED625068C57', 'appID': '3', 'userIP': '61.158.146.157', 'channelUserID': '76ab5a49ea40477f9623074d0d5e0227', 'newUser': 'false>\n', 'createTime': '2016-10-30 13:41:02.0'}

---

请参阅。

您也可以这样做：

import re

a = """2016-11-10 00:00:44,766 INFO [com.server.log.Log] - <Login Success. userInfo:  userID = 140803;appID = 3;channelID = 309;channelUserID = 76ab5a49ea40477f9623074d0d5e0227;userName = 1477806062675.ios.test;channelUserName = l379192229;createTime = 2016-10-30 13:41:02.0;loginTime = 1478707244762;userIP = 61.158.146.157;IMEI = FB7FE841-9E54-4421-86E0-1ED625068C57;newUser = false>"""
a = [re.split('\s*=\s*',b) for b in re.findall(r'(?:userInfo:\s*)(.*)', a)[0].split(';')]
d = dict(a)
d

步骤：

选择userInfo之后的所有内容： 分道扬镳； 在步骤2中循环浏览列表并在\s*=\s*上拆分。 从步骤3的列表列表中制作一本词典

---

您也可以这样做：

import re

a = """2016-11-10 00:00:44,766 INFO [com.server.log.Log] - <Login Success. userInfo:  userID = 140803;appID = 3;channelID = 309;channelUserID = 76ab5a49ea40477f9623074d0d5e0227;userName = 1477806062675.ios.test;channelUserName = l379192229;createTime = 2016-10-30 13:41:02.0;loginTime = 1478707244762;userIP = 61.158.146.157;IMEI = FB7FE841-9E54-4421-86E0-1ED625068C57;newUser = false>"""
a = [re.split('\s*=\s*',b) for b in re.findall(r'(?:userInfo:\s*)(.*)', a)[0].split(';')]
d = dict(a)
d

步骤：

选择userInfo之后的所有内容： 分道扬镳； 在步骤2中循环浏览列表并在\s*=\s*上拆分。 从步骤3的列表列表中制作一本词典

---

到目前为止你有没有尝试过？到目前为止你有没有尝试过？我使用这个模式来获得它：_login_success_pattern='.*userInfo:\s\s.*\s=\s.*=；|*.*\s=\s.*=[；|>]'我使用此模式获取它：uu登录u成功u模式='.*用户信息：\s\s.*？\s=\s.*=；|.*\s=\s.*=[；|>]'