使用不同列中的值在python中创建一个热编码

我有一个关于自助餐厅食物选项的数据框

df

：

Meal           Food         Cooked      Percentage 

Breakfast      Yes           Attended      1.00
Breakfast      Apple         No            .25
Breakfast      Oatmeal       Yes           .55
Breakfast      Skipped       Not           .20
Lunch          Yes           Attended      1.00
Lunch          Salad         No            .42
Lunch          Pizza         Yes           .48
Lunch          Skipped       Not           .10

我已经尝试了

pd.get_dummies（）

包，但这为

Cooked

类别列提供了二进制编码。我希望将我的数据集转换为：

Meal           Food         Cooked      Percentage   No    Yes    Not 

Breakfast      Yes           Attended      1.00     .25     .55    .20
Breakfast      Apple         No            .25      .25     .55    .20
Breakfast      Oatmeal       Yes           .55      .25     .55    .20
Breakfast      Skipped       Not           .20      .25     .55    .20
Lunch          Yes           Attended      1.00     .42     .48    .10
Lunch          Salad         No            .42      .42     .48    .10
Lunch          Pizza         Yes           .48      .42     .48    .10
Lunch          Skipped       Not           .10      .42     .48    .10

---

因此，我尝试根据第二列中的值将一列的值转换为新列。

让我们尝试

pivot

然后

reindex

+

join

s = df.pivot('Meal','Cooked','Percentage').reindex(df.Meal)
s.index = df.index
df = df.join(s)
df
Out[124]: 
        Meal     Food    Cooked  Percentage  Attended    No  Not   Yes
0  Breakfast      Yes  Attended        1.00       1.0  0.25  0.2  0.55
1  Breakfast    Apple        No        0.25       1.0  0.25  0.2  0.55
2  Breakfast  Oatmeal       Yes        0.55       1.0  0.25  0.2  0.55
3  Breakfast  Skipped       Not        0.20       1.0  0.25  0.2  0.55
4      Lunch      Yes  Attended        1.00       1.0  0.42  0.1  0.48
5      Lunch    Salad        No        0.42       1.0  0.42  0.1  0.48
6      Lunch    Pizza       Yes        0.48       1.0  0.42  0.1  0.48
7      Lunch  Skipped       Not        0.10       1.0  0.42  0.1  0.48

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