For循环For循环-Python

输出：

aabcbabccabc

如何获得这样的输出？：

---

aabbcc

您可以使用

zip

内置功能。它将返回您传递的所有iterables的第i项。看

就你而言：

l1 = ["a", "b", "c"]
l2 = ["a", "b", "c"]

for i in l1:
    print(i)
    for i in l2:
        print(i)

使用

zip

：

for it in zip(l1, l2):
    # the * is for extracting the items from it
    # sep="" does not print any spaces between
    # end="" does avoid printing a new line at the end
    print(*it, sep="", end="")

---

如果阵列大小相同，可以执行以下操作：

l1 = ["a", "b", "c"]
l2 = ["a", "b", "c"]


for a, b in zip(l1, l2):
  print(a)
  print(b)

---

我们可以使用下面的zip函数

for i in range((len(l1)):
    print(l1[i])
    print(l2[i])

---

谢谢你，亚历山大！谢谢你，罗尼。这就是我需要的

print(*(y for x in zip(l1,l2) for y in x))