Python 编写一个允许用户输入播放器的程序'；改变他们的名字和薪水

这是我在这方面取得的进展，但我不确定如何再次调用该过程：

Chelsea_Salaries_2014 = {'Jose Mourinho':[53, 163500, 'Unknown']}
Chelsea_Salaries_2014['Eden Hazard']=[22, 185000, 'June 2017']
Chelsea_Salaries_2014['Fernando Torres']=[29, 175000, 'June 2016']
Chelsea_Salaries_2014['John Terry']=[32, 175000, 'June 2015']
Chelsea_Salaries_2014['Frank Lampard']=[35, 125000, 'June 2014']
Chelsea_Salaries_2014['Ashley Cole']=[32, 120000, 'June 2014']
Chelsea_Salaries_2014['Petr Cech']=[31, 100000, 'June 2016']
Chelsea_Salaries_2014['Gary Cahill']=[27, 80000, 'June 2017']
Chelsea_Salaries_2014['David Luiz']=[26, 75000, 'June 2017']
Chelsea_Salaries_2014['John Obi Mikel']=[26, 75000, 'June 2017']
Chelsea_Salaries_2014['Nemanja Matic']=[25, 75000, 'June 2019']
Chelsea_Salaries_2014['Marco Van Ginkel']=[20, 30000, 'June 2018']
Chelsea_Salaries_2014['Ramires']=[26, 60000, 'June 2017']
Chelsea_Salaries_2014['Oscar']=[21, 67500, 'June 2017']
Chelsea_Salaries_2014['Lucas Piazon']=[19, 15000, 'June 2017']
Chelsea_Salaries_2014['Ryan Bertrand']=[23, 35000, 'June 2017']
Chelsea_Salaries_2014['Marko Marin']=[27, 35000, 'June 2017']
Chelsea_Salaries_2014['Cesar Azpilicueta']=[23, 55000, 'June 2017']
Chelsea_Salaries_2014['Branislav Ivanovic']=[29, 67500, 'June 2016']
Chelsea_Salaries_2014['Ross Turnbull']=[22, 17000, 'June 2017']
Chelsea_Salaries_2014['Demba Ba']=[28, 65000, 'June 2016']
Chelsea_Salaries_2014['Oriol Romeu']=[22, 15000, 'June 2015']

search_input = input('Welcome Jose. What player would you like to search for? ')
print('His Current Salary is £' + str(Chelsea_Salaries_2014[search_input][1]))
print()
new_salary = input('What would you like to change his salary to? ')

 if new_salary is 200000:
    print('Salary has been changed to £' + new_salary)
 else:
    if new_salary == >100000:
       print('This salary is ridiculous!')

试试这个：

search_input = input('Welcome Jose. What player would you like to search for? ')
print('His Current Salary is £' + str(Chelsea_Salaries_2014[search_input][1]))
print()
new_salary = int(input('What would you like to change his salary to? '))

if new_salary < 200000:
    print('Salary has been changed to £' + new_salary)
else:
    print('This salary is ridiculous!')

search\u input=input（'Welcome Jose.您想搜索哪位玩家？'））
打印（'他目前的工资是.'+str（切尔西工资2014[搜索输入][1]））
打印（）
new_salary=int（输入（'您希望将他的薪资更改为什么？'））
如果新员工工资<200000：
打印（'薪资已更改为“+”新薪资）
其他：
打印（‘这工资太荒谬了！’

一些评论：

new_salary is 200000

检查身份（两个对象是否相同）不相等（两个对象是否具有相同的值）；你想要

新的工资==200000

这仍然是行不通的，因为

new\u-salary

，就像你从

input

获得的一切一样，都是一个字符串；您可以使用

new\u salary=int（输入（…）

解决此问题

您的代码实际上并没有改变字典中的工资

Chelsea_Salories_2014

；为此，将新值分配回字典

Chelsea_Salaries_2014[search_input][1]=new_Salaries

---

您正在检查哪些值？如果新值小于或等于200000英镑，是否应更新该值？如果你被警告这是荒谬的，它应该被更新吗？你需要更仔细地思考逻辑是什么。例如，我认为您的第一个检查应该是

请阅读。只需将代码包含在一个循环中。。。do-例如，在按下一个特定键或写下一个保留名称之前，如果new_salary是200000:

不太可能做你想做的事-

new_salary

是一个字符串，在解释器中尝试

（100000*2）是200000

。@RodXavier，您应该已经推荐了本教程的内容。虽然例如添加

int

很有用，但您不需要复制整个代码来显示这一点（事实上，这样做会使发现更改变得更困难），并且说出您所做的事情会很有用。此外，这实际上并没有回答OP的问题（如何再次调用该过程）。200000是最大值。下面的任何内容都可以。谢谢这是一个真正的帮助

def change_salary(salaries):
    search_input = input('Welcome Jose. What player would you like to search for? ')
    print('His Current Salary is £{0:,}'.format(salaries[search_input][1]))
    new_salary = int(input('What would you like to change his salary to? '))
    if new_salary <= 200000:
        salaries[search_input][1] = new_salary
        print('Salary has been changed to £{0:,}'.format(new_salary))
    else:
        print('This salary is ridiculous!')

while True:
    change_salary(Chelsea_Salaries_2014)
    choice = input("Go again? y/n ")
    if choice.lower() in ('n', 'no'):
        break