Python 从列中删除大括号和word

我有这个问题，我想从数据框的列中删除大括号和一个单词。 这是称为“权重”的列：

  Weight
{'weight': 24}
{'weight': 24}
{'weight': 22}
{'weight': 17}
{'weight': 17}
{'weight': 11}
{'weight': 21}
{'weight': 16}
....

我想要的是：

  Weight
   24
   24
   22
   17
   17
   11
   21
   16
   ....

---

这怎么可能呢？谢谢

我想你有字典{'weight'：24}，而不是字符串“{'weight'：24}”

---

也许这很奇怪，但是你可以使用

str

来实现这一点

df['Weight'] = df['Weight'].str['weight']

df['Weight'] = df['Weight'].str.get('weight')

您还可以将

apply（）

与

lambda一起使用

df['Weight'] = df['Weight'].apply(lambda item: item['weight'])

df['Weight'] = df['Weight'].apply(lambda item: item.get('weight'))


最小工作代码

import pandas as pd

df = pd.DataFrame({'Weight':[
    {'weight': 24},
    {'weight': 24},
    {'weight': 22},
    {'weight': 17},
    {'weight': 17},
    {'weight': 11},
    {'weight': 21},
    {'weight': 16},
]})

print(df)

df['Weight'] = df['Weight'].str['weight']
#df['Weight'] = df['Weight'].str.get('weight')

#df['Weight'] = df['Weight'].apply(lambda item: item['weight'])
#df['Weight'] = df['Weight'].apply(lambda item: item.get('weight'))

print(df)


编辑：

您还可以将字典转换为
系列
，并获得
权重

df['Weight'] = df['Weight'].apply(pd.Series).get('weight')

df['Weight'] = df['Weight'].apply(pd.Series).explode('weight')

我假设您有字典
{'weight'：24}
，而不是字符串
“{'weight'：24}”


也许这很奇怪，但是你可以使用
str
来实现这一点

df['Weight'] = df['Weight'].str['weight']

df['Weight'] = df['Weight'].str.get('weight')

您还可以将
apply（）
与
lambda一起使用

df['Weight'] = df['Weight'].apply(lambda item: item['weight'])

df['Weight'] = df['Weight'].apply(lambda item: item.get('weight'))


最小工作代码

import pandas as pd

df = pd.DataFrame({'Weight':[
    {'weight': 24},
    {'weight': 24},
    {'weight': 22},
    {'weight': 17},
    {'weight': 17},
    {'weight': 11},
    {'weight': 21},
    {'weight': 16},
]})

print(df)

df['Weight'] = df['Weight'].str['weight']
#df['Weight'] = df['Weight'].str.get('weight')

#df['Weight'] = df['Weight'].apply(lambda item: item['weight'])
#df['Weight'] = df['Weight'].apply(lambda item: item.get('weight'))

print(df)


编辑：

您还可以将字典转换为
系列
，并获得
权重

df['Weight'] = df['Weight'].apply(pd.Series).get('weight')

df['Weight'] = df['Weight'].apply(pd.Series).explode('weight')

请发布您迄今为止尝试过的任何代码。
[row.get（“weight”）用于df[“weight”]
，如果您的列实际上是字典，请发布您迄今为止尝试过的任何代码。
[row.get（“weight”）用于df[“weight”]
，如果您的列实际上是字典。