Python Django开发：Chrome警告；更改密码"；

我是django的新手，为了学习，我创建了一个幻想项目。通过测试我的网站，Chrome浏览器警告我应该更改密码。确切的信息是

由于网站或应用程序中的数据泄露，您的密码被泄露。Chrome建议将密码更改为127.0.0.1:8000

我的代码中是否有任何内容导致此数据泄露

谢谢你的帮助

forms.py

class RegisterForm(forms.Form):

username = forms.CharField(
    label='Benutzername',
    max_length=150,
    required=True,
    widget=forms.TextInput(
        attrs={
            'placeholder': 'Username',
        }
    )
)

email = forms.EmailField(
    label='E-Mail Adresse',
    max_length=254,
    required=True,
    widget=forms.EmailInput(
        attrs={
            'placeholder': 'email@exapmle.com',
        }
    )
)

password = forms.CharField(
    label='Passwort',
    max_length=254,
    required=True,
    widget=forms.PasswordInput(
        attrs={
            'placeholder': 'Password',
        }
    )
)

repeatPassword = forms.CharField(
    label='Passwort wiederholen',
    max_length=254, required=True,
    widget=forms.PasswordInput(
        attrs={
            'placeholder': 'Password',
        }
    )
)

name = forms.CharField(
    label='Nachname',
    max_length=150,
    required=False,
    widget=forms.TextInput(
        attrs={
            'placeholder': 'Last Name',
        }
    )
)

firstName = forms.CharField(
    label='Vorname',
    max_length=150,
    required=False,
    widget=forms.TextInput(
        attrs={
            'placeholder': 'First name',
        }
    )
)

def clean(self):
    cleaned_data = super(RegisterForm, self).clean()
    username = cleaned_data.get('username')
    email = cleaned_data.get('email')
    password = cleaned_data.get('password')
    repeatPassword = cleaned_data.get('repeatPassword')
    name = cleaned_data.get('name')
    firstName = cleaned_data.get('firstName')

    if not username:
        raise forms.ValidationError('Enter Username')

    if User.objects.filter(username=username).exists():
        raise forms.ValidationError("Username is taken by another one")

    if not email:
        raise forms.ValidationError('Enter E-Mail')

    if User.objects.filter(email=email).exists():
        raise forms.ValidationError("E-Mail is taken by another one")

    if not password:
        raise forms.ValidationError('Enter password')

    if not repeatPassword:
        raise forms.ValidationError('Repeat password')

    if password != repeatPassword:
        raise forms.ValidationError('Passwords are not equal')

views.py

def register_view(request):
if request.method == 'POST':
    form = RegisterForm(request.POST)
    if form.is_valid():
        user = User.objects.create_user(username=request.POST['username'], email=request.POST['email'],
                                        password=request.POST['password'], first_name=request.POST['firstName'],
                                        last_name=request.POST['name'])

        user.save()

        # Get Created User from DB
        user = authenticate(request, username=request.POST['username'], password=request.POST['password'])
        if user:
            # LogIn (create Session etc...)
            login(request, user)

            # open user.html
            return render(request, 'web/user.html')
    return render(request, 'web/register.html', {'form': form})
else:
    form = RegisterForm()
    return render(request, 'web/register.html', {'form': form})

---

似乎这条消息只是一个信息，使用了弱密码。

---

多亏了顽强的B澄清了这一点。

您的代码很好，当您使用弱密码时，Chrome确实会显示这样的警告。无需担心。

这并不是说您的应用程序或帐户被泄露，只是意味着您使用的是一个经过pwnd的超弱密码（如password123）。如果您只是为本地测试创建一个帐户，那么不用担心，但您可能不应该在现实生活中使用该密码。看这里：好的，谢谢你的帮助。这条信息真是让人困惑：我第一次就把我干掉了，这是肯定的