Python中的CSV文件处理

我使用以下格式输出到文本文件的空间数据：

COMPANY NAME
P.O. BOX 999999
ZIP CODE , CITY 
+99 999 9999
23 April 2013 09:27:55

PROJECT: Link Ref
--------------------------------------------------------------------------------
--------------------------------------------------------------------------------
Design DTM is 30MB 2.5X2.5
Stripping applied to design is 0.000

Point Number      Easting     Northing        R.L. Design R.L.  Difference  Tol  Name
     3224808   422092.700  6096059.380       2.520     -19.066     -21.586  --   
     3224809   422092.200  6096059.030       2.510     -19.065     -21.575  --   
<Remainder of lines>
 3273093   422698.920  6096372.550       1.240     -20.057     -21.297  --   

Average height difference is -21.390
RMS  is  21.596
0.00 % above tolerance
98.37 % below tolerance
End of Report

问题:

• 如何让以“点编号”开头的行成为输出文件的标题？我试图用DictReader代替reader/writer位，但无法使其工作

• 使用分隔符“”写入输出文件确实有效，但会在每个空格处写入一个逗号，使输出文件中的空列过多。我该如何避免这种情况

• 如何删除页脚

---

我发现您的代码有问题，您正在为每一行创建一个新的

编写器
；所以你只会得到最后一个

您的代码可以是这样的，不需要CSV阅读器或编写器，因为它足够简单，可以解析为简单的文本（如果您有文本列，带有转义字符等等，就会出现问题）

回答您的第一个和最后一个问题：这只是关于忽略相应的行，即不将它们写入输出。这对应于fortran建议的
如果未找到标题
和
否则如果未找到行：
块

第二点是，您的文件中没有专用的分隔符：您有一个或多个空格，这使得使用
csv
module解析很困难。使用
split（）

#! /usr/bin/env python

import glob,os

list_of_files = glob.glob('C:/test/*.txt')

def process_file(source, dest):
  header_found = False
  for line in source:
    line = line.strip()
    if not header_found:
      #ignore everything until we find this text
      header_found = line.startswith('Stripping applied') #otherwise, header is lost
    elif not line:
      return #we are done when we find an empty line
    else:
      #write the needed columns
      columns = line.split()
      dest.writelines(','.join(columns[i] for i in (1, 2, 5))+"\n") #newline character adding was necessary

for filename in list_of_files:
  short_filename, extension = os.path.splitext(filename)
  file_out_name = short_filename + '_ed' + ".csv"
  with open(filename, 'r') as source:
    with open(file_out_name, 'wb') as dest:
      process_file(source, dest)

感谢您的快速回答。请使用
elif
而不是
else，如果使用
+1来指示转义字符，这可能是一个内置函数难以处理的问题。请单击答案左侧的大勾线框，奖励为您提供最佳ID的用户，好吗？
def process_file(source, dest):
  found_header = False
  for line in source:
    line = line.strip()
    if not header_found:
      #ignore everything until we find this text
      header_found = line.starswith('Point Number')
    elif not line:
      return #we are done when we find an empty line, I guess
    else:
      #write the needed columns
      columns = line.split()
      dest.writeline(','.join(columns[i] for i in (1, 2, 5)))

for filename in list_of_files:
  short_filename, extension = os.path.splitext(filename)
  file_out_name = short_filename + '_ed' + extension
  with open(filename, 'r') as source:
    with open(file_out_name. 'w') as dest:
      process_file(source, dest)

#! /usr/bin/env python

import glob,os

list_of_files = glob.glob('C:/test/*.txt')

def process_file(source, dest):
  header_found = False
  for line in source:
    line = line.strip()
    if not header_found:
      #ignore everything until we find this text
      header_found = line.startswith('Stripping applied') #otherwise, header is lost
    elif not line:
      return #we are done when we find an empty line
    else:
      #write the needed columns
      columns = line.split()
      dest.writelines(','.join(columns[i] for i in (1, 2, 5))+"\n") #newline character adding was necessary

for filename in list_of_files:
  short_filename, extension = os.path.splitext(filename)
  file_out_name = short_filename + '_ed' + ".csv"
  with open(filename, 'r') as source:
    with open(file_out_name, 'wb') as dest:
      process_file(source, dest)