Python 如何连接两个独立的字符串

我需要连接两条线

第一个字符串=日期：

(MegaMillions2019 = (date.strftime("%m%d%Y")))

第二个字符串=结果：

(results = '\n'.join([', '.join(parsed[i]) for i in range(len(parsed))])
(results.replace(' ','')))

这些字符串需要在下面显示的同一行上

代码：

输出日期：

01222019
01182019
01152019
01112019
01082019
01042019
01012019

结果:

8,16,30,38,61,10
4,15,37,59,64,16
2,43,48,62,64,24
29,52,58,60,62,7
4,5,31,62,69,20
13,26,29,38,64,5
21,29,35,54,60,15

我希望他们像这样结合在一起：

01222019,8,16,30,38,61,10
01182019,4,15,37,59,64,16
01152019,2,43,48,62,64,24
01112019,29,52,58,60,62,7
01082019,4,5,31,62,69,20
01042019,13,26,29,38,64,5
01012019,21,29,35,54,60,15

---

您可以执行以下操作

MegaMillions2019 =[]
for date in date:
    date2 = (date.get_text())
    date = (datetime.strptime(date2, '%b %d, %Y'))
    MegaMillions2019.append(date.strftime("%m%d%Y")))
...

for mm, r in zip(MegaMillions2019, results.replace(' ','')): 
    print (f"{mm}, {r}")

---

保留两个列表

l1

和

l2

，在第一个循环中的

l1

中追加日期，在第二个循环中的

l2

中追加结果列表

例如：

l1=[012220190122202901222013]
l2=[[3,4,5]，[1,2,3]，[4,5,5]]

然后，您可以按如下方式压缩这两个列表：

new_list = [",".join(map(str, (list(a) + b))) for a, b in zip(s1, s2)]

现在您可以打印新的_列表，该列表将有逗号分隔的结果

dates = []
for date in date:
    ...
    dates.append(str(MegaMillions2019))

...

parsed = []
joined = []
for i in range(int(len(data)/7)):
    j = i*7
    parsed.append(data[j:j+6])
    parsedline = [', '.join(parsed[j]) for j in range(len(parsed))][i]
    joined.append(dates[i]+', '+ parsedline)

results = '\n'.join(joined)
print(results.replace(' ',''))

演示：

输出样本：

03292019,5,14,15,62,66,3
03262019,4,14,22,43,58,9

---

使用单独的列表存储日期，并使用打印元素，如果列表中的任何元素缺失，则将使用

None

填充，而不是缺失元素：

制作一个迭代器，聚合来自每个ITerable的元素。 如果iterables的长度不均匀，则会填充缺少的值 具有填充值。迭代将继续，直到找到最长的iterable 筋疲力尽

因此：

import requests
from bs4 import BeautifulSoup
from datetime import datetime

response = requests.get('https://www.lotterycorner.com/mi/mega-millions/2019')
soup = BeautifulSoup(response.text, 'html.parser')
date = soup.find_all("td", {"class":"win-nbr-date col-sm-3 col-xs-4"})
megaList = []                                    # empty list for dates
for date in date:
    date2 = (date.get_text())
    date = (datetime.strptime(date2, '%b %d, %Y'))
    MegaMillions2019 = (date.strftime("%m%d%Y"))
    megaList.append(MegaMillions2019)

data = []
for ultag in soup.find_all("ul",{"class":"nbr-grp"}):
    for litag in ultag.find_all('li'):
        results = (litag.get_text().replace(' ','').replace('MegaBall',''))
        data.append(results)

parsed = []
for i in range(int(len(data)/7)):
    j = i*7
    parsed.append(data[j:j+6])

results = [', '.join(parsed[i]) for i in range(len(parsed))]
results = [i.replace(' ','') for i in results]     # remove space from each elem in results

for mg, res in zip_longest(megaList, results):
print(mg, res, sep =',')

03292019,5,14,15,62,66,3
03262019,4,14,22,43,58,9
.
.
01252019,8,16,30,38,61,10
01222019,4,15,37,59,64,16
01182019,2,43,48,62,64,24
.
.
01042019,21,29,35,54,60,15
01012019,34,44,57,62,70,14

输出：

import requests
from bs4 import BeautifulSoup
from datetime import datetime

response = requests.get('https://www.lotterycorner.com/mi/mega-millions/2019')
soup = BeautifulSoup(response.text, 'html.parser')
date = soup.find_all("td", {"class":"win-nbr-date col-sm-3 col-xs-4"})
megaList = []                                    # empty list for dates
for date in date:
    date2 = (date.get_text())
    date = (datetime.strptime(date2, '%b %d, %Y'))
    MegaMillions2019 = (date.strftime("%m%d%Y"))
    megaList.append(MegaMillions2019)

data = []
for ultag in soup.find_all("ul",{"class":"nbr-grp"}):
    for litag in ultag.find_all('li'):
        results = (litag.get_text().replace(' ','').replace('MegaBall',''))
        data.append(results)

parsed = []
for i in range(int(len(data)/7)):
    j = i*7
    parsed.append(data[j:j+6])

results = [', '.join(parsed[i]) for i in range(len(parsed))]
results = [i.replace(' ','') for i in results]     # remove space from each elem in results

for mg, res in zip_longest(megaList, results):
print(mg, res, sep =',')

03292019,5,14,15,62,66,3
03262019,4,14,22,43,58,9
.
.
01252019,8,16,30,38,61,10
01222019,4,15,37,59,64,16
01182019,2,43,48,62,64,24
.
.
01042019,21,29,35,54,60,15
01012019,34,44,57,62,70,14

---

您当前获得的输出是什么？是否将它们一起添加到列表中？或者压缩它们？你可以使用zip。我当前得到的输出是打印在结果顶部的日期。不，不起作用，再次查找

megamillion2019

。不，它仍然不会。你遗漏了什么，请在OP中查找

results

。这是一个逗号分隔的字符串。打印（megamillion2019）在第14行，把它从演示中删除，你是说？完成。运行该程序时，您会将日期堆叠在日期/结果字符串的顶部。谢谢大家的帮助。请再试一次。