Python Django can'；找不到URL模式

我不明白为什么Django无法在我的应用程序中找到请求的URL

以下是我得到的错误代码：

 Using the URLconf defined in littlelogsms.urls, Django tried these URL patterns, in this order:
^admin/
^$
The current URL, success/, didn't match any of these.

这是我的sms.url.py文件：

from django.conf.urls import url

from sms import views

urlpatterns = [
    url(r'^success/$', views.success, name='success'),
    url(r'^$', views.index, name='index')
]

from django.conf.urls import include, url
from django.contrib import admin


urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    url(r'^$', include('sms.urls')),
]

下面是应用程序url.py文件：

from django.conf.urls import url

from sms import views

urlpatterns = [
    url(r'^success/$', views.success, name='success'),
    url(r'^$', views.index, name='index')
]

from django.conf.urls import include, url
from django.contrib import admin


urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    url(r'^$', include('sms.urls')),
]

---

我找不到我犯的错误。有什么想法吗？

这个问题是这个url模式中的美元符号

url(r'^$', include('sms.urls')),

插入符号

^

匹配字符串的开头，美元

$

匹配字符串的结尾，因此

^$

仅匹配索引URL

/

您应该删除美元并将其更改为：

url(r'^', include('sms.urls')),

---

您应该尝试使用基本url，如

以下是应用程序URL.py文件：

from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^sms', include('sms.urls')),   # 'sms' is your defined name
]

from django.conf.urls import url

from sms import views

urlpatterns = [
    url(r'^success/$', views.success, name='success'),
    url(r'^$', views.index, name='index')
]

这是我的sms.urls.py文件：

from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^sms', include('sms.urls')),   # 'sms' is your defined name
]

from django.conf.urls import url

from sms import views

urlpatterns = [
    url(r'^success/$', views.success, name='success'),
    url(r'^$', views.index, name='index')
]

您应该尝试访问您的url，就像在您的视图中一样

sms///用于访问视图中的tht索引函数 sms/success//用于访问视图中的success函数

或者您可以使用模板中表单操作标记中的标签来调用URL

---

{%url'sms:index或success%}//index，success是sms中给定的名称空间。url

谢谢！！我知道这是一件非常简单的事情，但我没有得到：）