替换Python中的单个dict元素

我试图用每个对象都有一个字符串列表来填充对象的dict，所有对象都来自给定的字符串列表。问题是，当我想替换dict的单个元素时，每个元素都会发生变化

人员类别：

class Person:

    messages = []

    def __init__(self, p):
        self.name = p

    def add_message(self, m_text):
        self.messages.append(m_text)

主要代码：

chat_messages_list = ["Eva: Eva's first text", "Eva: Eva's second text", "Eva: Eva's third text",
                      "Harry: Harry's first text", "Harry: Harry's second text", "Harry: Harry's third text",
                      "Ellis: Ellis' first text", "Ellis: Ellis' second text", "Ellis: Ellis' third text"]
dict_persons = {}

for element in chat_messages_list:

    split_messages = element.split(": ")
    name = split_messages[0]
    message_text = split_messages[1]

    # Create Person in list if not already exists
    if name not in dict_persons:
        dict_persons[name] = Person(name)

    person = dict_persons[name]

    # THE PROBLEM: Following line will add message_text to EVERY Person in dict_persons
    person.add_message(message_text)

for key, value in dict_persons.items():
    print("{0}: {1}".format(key, value.messages))

预期结果：

Eva: ["Eva's first text", "Eva's second text", "Eva's third text"]
Harry: ["Harry's first text", "Harry's second text", "Harry's third text"]
Ellis: ["Ellis' first text", "Ellis' second text", "Ellis' third text"]

实际结果：

Eva: ["Eva's first text", "Eva's second text", "Eva's third text", "Harry's first text", "Harry's second text", "Harry's third text", "Ellis' first text", "Ellis' second text", "Ellis' third text"]
Ellis: ["Eva's first text", "Eva's second text", "Eva's third text", "Harry's first text", "Harry's second text", "Harry's third text", "Ellis' first text", "Ellis' second text", "Ellis' third text"]
Harry: ["Eva's first text", "Eva's second text", "Eva's third text", "Harry's first text", "Harry's second text", "Harry's third text", "Ellis' first text", "Ellis' second text", "Ellis' third text"]

---

Wy是添加到dict中所有对象的字符串，而不是所需的字符串吗？

尝试将

消息=[]

放在init中：

class Person:

    def __init__(self, p):
        self.name = p
        self.messages = []

    def add_message(self, m_text):
        self.messages.append(m_text)

---

这对我有用

尝试将

消息=[]

放在您的init中：

class Person:

    def __init__(self, p):
        self.name = p
        self.messages = []

    def add_message(self, m_text):
        self.messages.append(m_text)

---

这对我有用

初始化

人员的
\uuuuu init\uuuuu
中的
消息
字段，即
self.messages=[]
使其成为实例字段。

现在它是一个类级字段，因此所有实例共享同一个列表。
初始化
消息
位于
人的
\uuuuuuuuu
中的
初始化
字段，即
self.messages=[]
使其成为实例字段。

现在它是一个类级字段，因此所有实例共享同一个列表。
是的，当然，因为您要附加到同一个列表，也就是说，您要附加到您在类中定义为
messages=[]
的列表，这是所有实例共享的类级属性。是的，当然，因为您要附加到同一个列表，也就是说，您将添加到在类中定义为
messages=[]
的列表中，该列表是所有实例共享的类级属性。