ValueError：（Django1.11.1 python3.6.1 pycharm）_Python_Django_Pycharm

ValueError：（Django1.11.1 python3.6.1 pycharm）

python django pycharm

ValueError：（Django1.11.1 python3.6.1 pycharm）,python,django,pycharm,Python,Django,Pycharm,当我尝试使用index.html中设置的用户名和密码登录时，出现如下错误： ValueError at /login_action/ The view sign.views.login_action didn't return an HttpResponse object. It returned None instead. Request Method: POST Request URL: http://127.0.0.1:8000/login

当我尝试使用index.html中设置的用户名和密码登录时，出现如下错误：

ValueError at /login_action/
The view sign.views.login_action didn't return an HttpResponse object. It                       returned None instead.
Request Method: POST
Request URL:    http://127.0.0.1:8000/login_action/
Django Version: 1.11.1
Exception Type: ValueError
Exception Value:    
The view sign.views.login_action didn't return an HttpResponse object. It returned None instead.
Exception Location: D:\python3.6.1\lib\site-      packages\django\core\handlers\base.py in _get_response, line 198
Python Executable:  D:\python3.6.1\python.exe
Python Version: 3.6.1
Python Path:    
['C:\\Users\\Administrator\\guest',
'D:\\python3.6.1\\python36.zip',
'D:\\python3.6.1\\DLLs',
'D:\\python3.6.1\\lib',
'D:\\python3.6.1',
'D:\\python3.6.1\\lib\\site-packages']
 Server time:   Mon, 12 Jun 2017 08:29:35 +0000

从提示中可以看出，HttpResponse对象的值为none

url.py如下所示

from django.conf.urls import url
from django.contrib import admin
from sign import views
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^index/$',views.index),
url(r'^login_action/$',views.login_action),
]

from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
def index(request):
return render(request,"index.html")
# 登录函数定义
def login_action(request):
 if request.method == 'post':
    username = request.POST.get('username','')
    password = request.POST.get('password','')
    if username == 'admin'and password == 'admin123':
        return HttpResponse( '恭喜您，登录成功!')
    else:
        return render(request,'index.html',{'error':'用户名或者登录密码错误!'})

<html>
<head>
    <title>欢迎登陆点米年会发布会系统</title>
</head>
<body>
<h1>年会签名系统登陆<br>
    WELCOM TO DIAN MI</h1>
<form method="post" action="/login_action/">
<input name="username" type="text" placeholder="用户名"><br>
<input name="password" type="password" placeholder="登录密码"><br>
    <button id="btn"  type="submit"> 登陆</button>
{{error}}<br>
</form>
</body>
</html>

views.py如下所示

from django.conf.urls import url
from django.contrib import admin
from sign import views
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^index/$',views.index),
url(r'^login_action/$',views.login_action),
]

from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
def index(request):
return render(request,"index.html")
# 登录函数定义
def login_action(request):
 if request.method == 'post':
    username = request.POST.get('username','')
    password = request.POST.get('password','')
    if username == 'admin'and password == 'admin123':
        return HttpResponse( '恭喜您，登录成功!')
    else:
        return render(request,'index.html',{'error':'用户名或者登录密码错误!'})

<html>
<head>
    <title>欢迎登陆点米年会发布会系统</title>
</head>
<body>
<h1>年会签名系统登陆<br>
    WELCOM TO DIAN MI</h1>
<form method="post" action="/login_action/">
<input name="username" type="text" placeholder="用户名"><br>
<input name="password" type="password" placeholder="登录密码"><br>
    <button id="btn"  type="submit"> 登陆</button>
{{error}}<br>
</form>
</body>
</html>

index.html如下所示

from django.conf.urls import url
from django.contrib import admin
from sign import views
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^index/$',views.index),
url(r'^login_action/$',views.login_action),
]

from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
def index(request):
return render(request,"index.html")
# 登录函数定义
def login_action(request):
 if request.method == 'post':
    username = request.POST.get('username','')
    password = request.POST.get('password','')
    if username == 'admin'and password == 'admin123':
        return HttpResponse( '恭喜您，登录成功!')
    else:
        return render(request,'index.html',{'error':'用户名或者登录密码错误!'})

<html>
<head>
    <title>欢迎登陆点米年会发布会系统</title>
</head>
<body>
<h1>年会签名系统登陆<br>
    WELCOM TO DIAN MI</h1>
<form method="post" action="/login_action/">
<input name="username" type="text" placeholder="用户名"><br>
<input name="password" type="password" placeholder="登录密码"><br>
    <button id="btn"  type="submit"> 登陆</button>
{{error}}<br>
</form>
</body>
</html>


欢迎登陆点米年会发布会系统
年会签名系统登陆

欢迎来到滇米




登陆
{{error}}

尝试将测试字符串更改为大写。正如您在request.method的字符串中所看到的，它们不是小写

更好方法名称使用大写字母：

如果request.method==“POST”：

好多了 使用基于类的视图：

类登录操作（视图）： def post（自我，请求）：
你的代码

将

request.method

大写，如

if request.method == 'POST':

第

request.method==“POST”

行上的“POST”检查需要在views.py文件中使用大写字母。

完全不同意第2点-基于类的视图有它们的用例，但它们现在比基于函数的视图“更好”（就像锤子比螺丝刀“更好”）。将http方法映射到适当的类方法，若不允许使用方法，则引发405，这就是视图所做的。在这里看不到基于类的视图的问题。当我看到模式'if request.method='XXXX'。。。我认为在基于类的视图中实现post方法更具可读性。@KePe非常感谢，它确实来自案例问题