python中元组列表中的随机值

我试图从python中的以下输入类型中获得一些随机的5或8个值

[(1, (0.0, 1.1)), (2, (0.0, 2.21)), (3, (0.0, 3.31)), (5, (0.0, 4.41)), 
(5,(0.0, 5.51)), (6, (0.0, 6.62)), (7, (0.0, 7.72)), (8, (0.04, 0.0)), 
(9, (0.04, 1.1)), (10, (0.04, 2.21)), (11, (0.04, 2.21)), (12, (0.04, 3.31)), 
(13, (0.04, 3.31)), (14, (0.04, 4.41))]

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我如何才能得到它？

首先，您需要将元组列表转换为字典：

l = [(1, (0.0, 1.1)), (2, (0.0, 2.21)), (3, (0.0, 3.31)), (5, (0.0, 4.41)), 
(5,(0.0, 5.51)), (6, (0.0, 6.62)), (7, (0.0, 7.72)), (8, (0.04, 0.0)), 
(9, (0.04, 1.1)), (10, (0.04, 2.21)), (11, (0.04, 2.21)), (12, (0.04, 3.31)), 
(13, (0.04, 3.31)), (14, (0.04, 4.41))]

d = dict(l)

要获得8个随机键，请使用：

要获取相应的值，可以使用：

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首先，正如几位评论者所提到的，您在问题上发布的输入是

元组的
列表，而不是
dict
。除此之外，要从集合中获取随机值，可以使用：，或从python标准库中获取

您可以这样调用函数：

import random
your_input = [(1, (0.0, 1.1)), (2, (0.0, 2.21)), (3, (0.0, 3.31)),
              (5, (0.0, 4.41)), (5,(0.0, 5.51)), (6, (0.0, 6.62)),
              (7, (0.0, 7.72)), (8, (0.04, 0.0)), (9, (0.04, 1.1)),
              (10, (0.04, 2.21)), (11, (0.04, 2.21)), (12, (0.04, 3.31)), 
              (13, (0.04, 3.31)), (14, (0.04, 4.41))]

# Let's take one random number
one_choice = random.choice(your_input)

# Let's sample 10 random numbers from the list without replacement
n_samples = random.sample(your_input, k=10)

# Let's take 10 random numbers from the list **with** replacement
n_samples = random.choices(your_input, k=10)

import operator
randomvalues = operator.itemgetter(*randomkeys)(d)

import random
your_input = [(1, (0.0, 1.1)), (2, (0.0, 2.21)), (3, (0.0, 3.31)),
              (5, (0.0, 4.41)), (5,(0.0, 5.51)), (6, (0.0, 6.62)),
              (7, (0.0, 7.72)), (8, (0.04, 0.0)), (9, (0.04, 1.1)),
              (10, (0.04, 2.21)), (11, (0.04, 2.21)), (12, (0.04, 3.31)), 
              (13, (0.04, 3.31)), (14, (0.04, 4.41))]

# Let's take one random number
one_choice = random.choice(your_input)

# Let's sample 10 random numbers from the list without replacement
n_samples = random.sample(your_input, k=10)

# Let's take 10 random numbers from the list **with** replacement
n_samples = random.choices(your_input, k=10)