如何使python接受随机输入

我目前正在从事一个python项目，我需要它在某个时候接受用户的随机输入

因此，如果我有，例如：

def question_one () :
    answer_one = raw_input ('How many days are there in a week? ').lower()
    try: 
        if answer_one == 'seven' or answer_one == '7' :
            question_2()

凡事都能创造奇迹。但是如何让python接受随机输入，如中所示

def question_two () :
    answer_two = raw_input ('What´s your mother´s name? ').lower()
    try: 
        if answer_two == ***I have no idea how to code this part*** :
            question_3()

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在这种情况下，我需要python来接受任何输入，并且仍然让用户进入下一个问题。我该怎么做呢？

如果输入不必是特定的形式，或者没有特定的属性，那么就不需要If语句，甚至不需要try

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只需删除if子句即可

如果你想重新问这个问题，如果他们没有答对，你可以像这样回过头来问。这个问题唯一可以接受的答案是“是”，或者“是”，等等。。 如果他们回答不正确，它会再次询问他们，直到他们答对为止

def question1():
    answer1 = raw_input("Do you like chickens?")
    answer1 = answer1.lower()
    if answer1 == 'yes':
        print "That is Correct!"
        question2()
    else:
        question1()

如果你想让他们即使错了也能继续下一个问题，你可以这样做：

def question1():
    answer1 = raw_input("Do you like chickens?")
    answer1 = answer1.lower()
    if answer1 == 'yes':
        print "That is Correct!"
    else:
        print "Next question coming!"
    question2()

def question2():
    answer2 = raw_input("How many days in a week?")
    answer2 = answer2.lower()
    if answer2 == '7' or answer2 == "seven":
        print "That is Correct!"
    else:
        print "Sorry,that was wrong"
    question3()

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在第二个示例中，为if…else子句的两个分支调用question2很容易出错。把它搬到外面去，谢谢！是的，那是我的问题。

def question1():
    answer1 = raw_input("Do you like chickens?")
    answer1 = answer1.lower()
    if answer1 == 'yes':
        print "That is Correct!"
    else:
        print "Next question coming!"
    question2()

def question2():
    answer2 = raw_input("How many days in a week?")
    answer2 = answer2.lower()
    if answer2 == '7' or answer2 == "seven":
        print "That is Correct!"
    else:
        print "Sorry,that was wrong"
    question3()