Python 如何打开子窗口？

请帮助修复脚本

import tkinter

def winMake(parent):
    win = tkinter.Frame(parent)
    win.config(relief = 'sunken', width = 340, height = 170, bg = 'red')
    win.pack(expand = 'yes', fill = 'both')

    msg = tkinter.Button(win, text='press me', command = addFormOpen)
    msg.pack()

def addFormOpen():
    addForm = tkinter.Toplevel(root)
    Label(addForm, text = 'ertert').pack()
    print('fff')

root = tkinter.Tk()
winMake(root)
root.mainloop()

点击按钮后，“按我”将打开一个子窗口。但控制台会显示一条错误消息：

Exception in Tkinter callback Traceback (most recent call last):  
  File "C:\Python33\lib\tkinter\__init__.py", line 1475, in __call__
    return self.func(*args)   File "C:\Python33\projects\DVD_LIS\p3_dvd_list_shelve_3d_class_edit_menubar\q.py", line 13, in addFormOpen
    Label(addForm, text = 'ertert').pack() 
NameError: global name 'Label' is not defined

---

您导入了包含类

标签的名称
tkinter
。也就是说，为了访问它，您需要将
tkinter.
放在它前面（就像您对
帧
，
按钮
等所做的那样）：

否则，Python将不知道在哪里定义了
标签

tkinter.Label(addForm, text = 'ertert').pack()