Python While循环作为成绩计算器，与完成的作业数量#相关

到目前为止，这是我的while循环。我问用户他们完成了多少作业，只能在1到10之间（从0到5分）

但是，如果他们回答10以下的任何问题，我希望to代码自动将其输入为零，而不是用户必须为他们尚未完成的每个任务手动输入0

现在我的代码会要求用户输入10次成绩，但我只想根据用户完成多少作业的答案输入成绩。因此，如果他们回答了7个问题，那么这个问题将被呈现7次，三个0分将自动计入平均值

while True:
   
    result = input("How many assignments did you complete? ")
   
  if result.isdigit() and 0 <= int(result) <= 10:
         break;
     print ("Try a number between 1 and 10") 
total = 0
gradeCount = 0
while gradeCount < 10:
    grade = float(input('What was assignment score: '))
    if grade < 0 or grade > 5:
        print('It should be a number from 0 to 5')
    else:
        gradeCount += 1
        total += grade
aaverage = total / 30 * 100
print('Average: ', aaverage)

为True时：
结果=输入（“您完成了多少作业？”）
如果result.isdigit（）和0
为True：
结果=输入（“您完成了多少作业？”）
如果result.isdigit（）和0
，而1：
结果=输入（“您完成了多少作业？”）
如果result.isdigit（）和0感谢您花时间帮助我，您的代码完全按照我想要的方式执行，但我很好奇，while 1与while True在原则上相同吗？有没有一个原因让我们想要一种方式而不是另一种方式？我建议阅读：
while True:
   
    result = input("How many assignments did you complete? ")
    if result.isdigit() and 0 <= int(result) <= 10:
         break;
    print ("Try a number between 1 and 10") 
total = 0
gradeCount = 0
while gradeCount < int(result):
    grade = float(input('What was assignment score: '))
    if grade < 0 or grade > 5:
        print('It should be a number from 0 to 5')
    else:
        gradeCount += 1
        total += grade
aaverage = total / 50 * 100
print('Average: ', aaverage)

while 1:
    result = input("How many assignments did you complete? ")
    if result.isdigit() and 0 <= int(result) <= 10:
         result = int(result)
         break
     print ("Try a number between 1 and 10") 
total = 0
for i in range(result):
    while 1:
        grade = float(input('What was assignment score: '))
        if 0 <= grade <= 5:
            break
        else:
            print('It should be a number from 0 to 5')
    total += grade
aaverage = total / 10
print('Average: ', aaverage)