Python 从dict列表创建dict

我有一个字典列表，看起来像这样->

  list =  [{"id":1,"path":"a/b", ........},
           {"id":2,"path":"a/b/c", ........},
           {"id":3,"path":"a/b/c/d", ........}]

   d=dict()
   d["a/b"] = 1
   d["a/b/c"] = 2
   d["a/b/c/d"] = 3

现在我想创建一个路径到id映射的dict。 应该是这样的->

  list =  [{"id":1,"path":"a/b", ........},
           {"id":2,"path":"a/b/c", ........},
           {"id":3,"path":"a/b/c/d", ........}]

   d=dict()
   d["a/b"] = 1
   d["a/b/c"] = 2
   d["a/b/c/d"] = 3

如何以pythonic的方式创建它

d = {i['path']:i['id'] for i in list}

可能是这样的：

d = {x["path"]: x["id"] for x in list_of_dicts}

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大概是这样吧

list =  [{"id":1,"path":"a/b", "test":"1"},{"id":2,"path":"a/b/c", "test":"2"}, {"id":3,"path":"a/b/c/d", "test":"3"}]
d={}
for i in list:
    d[i['path']]=d['id']
print d

这是输出：

{'a/b/c'：2'a/b/c/d'：3'a/b'：1}

输出：

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到目前为止你试过什么？