Python使用备用字母表加密字符串
我不知道该怎么做。我需要加密给定不同字母表的字符串Python使用备用字母表加密字符串,python,string,encryption,Python,String,Encryption,我不知道该怎么做。我需要加密给定不同字母表的字符串 def substitute(string, ciphertext): alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" encrypted = [] list(alphabet) list(ciphertext) encrypted = "" for x in string: if x.isalpa(): encrypted.
def substitute(string, ciphertext):
alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
encrypted = []
list(alphabet)
list(ciphertext)
encrypted = ""
for x in string:
if x.isalpa():
encrypted.append(ciphertext[x])
else:
encrypted.append(x)
word = string.join(encrypted)
print(encrypted)
return encrypted
试试这个:
def substitute(string, ciphertext):
alphabet = list("ABCDEFGHIJKLMNOPQRSTUVWXYZ") # list() returns a list,
ciphertext = list(ciphertext) # it doesn't change (mutate) the variable
encrypted = [] # Not sure why you were storing the empty string here,
# but strings cannot use the append() method.
for x in string:
if x.isalpha(): # Fixed a typo
# Here I think you want to use alphabet.index(x) instead of x.
encrypted.append(ciphertext[alphabet.index(x)])
else:
encrypted.append(x)
return "".join(encrypted) # Turning the list into a string
正如另一位评论者所说,在将来,请添加示例,说明您做了什么,而不是您的代码要做什么
我建议你查一下易变性的定义,因为这似乎是你正在努力解决的问题。到底什么不起作用?你能提供一个预期输入和输出的例子吗?不是加密,而是编码。你知道的越多。。。