Python 捕获线程中中断的系统调用
我有一个使用Envisige框架的客户机-服务器应用程序,我使用线程来处理连接,下面是代码中的一个令牌Python 捕获线程中中断的系统调用,python,multithreading,asyncsocket,Python,Multithreading,Asyncsocket,我有一个使用Envisige框架的客户机-服务器应用程序,我使用线程来处理连接,下面是代码中的一个令牌 .... SocketServer.TCPServer.allow_reuse_address = True self.server = TCPFactory( ( HOST, PORT ), TCPRequestHandler, self.application) self.server_thread = thr
....
SocketServer.TCPServer.allow_reuse_address = True
self.server = TCPFactory( ( HOST, PORT ), TCPRequestHandler, self.application)
self.server_thread = threading.Thread( target = self.server.serve_forever )
self.server_thread.setDaemon( True )
self.server_thread.start()
class TCPFactory( SocketServer.ThreadingTCPServer ):
def __init__( self, server_address, RequestHandlerClass, application ):
SocketServer.ThreadingTCPServer.__init__( self, server_address, RequestHandlerClass )
self.application = application
class TCPRequestHandler( SocketServer.BaseRequestHandler ):
""""""
def setup( self ):
.....
在Envisige框架中,我调用了open\u file()
函数,它给了我们一个弹出窗口,但是当这个窗口出现时,我收到了以下错误
Exception in thread Thread-2:
Traceback (most recent call last):
File "/usr/lib/python2.7/threading.py", line 551, in __bootstrap_inner
self.run()
File "/usr/lib/python2.7/threading.py", line 504, in run
self.__target(*self.__args, **self.__kwargs)
File "/usr/lib/python2.7/SocketServer.py", line 225, in serve_forever
r, w, e = select.select([self], [], [], poll_interval)
error: (4, 'Interrupted system call')
如何处理此错误?在Armin Rigo发表评论后,我修改了SockeServer.py
def serve_forever(self, poll_interval=0.5):
"""Handle one request at a time until shutdown.
Polls for shutdown every poll_interval seconds. Ignores
self.timeout. If you need to do periodic tasks, do them in
another thread.
"""
self.__is_shut_down.clear()
try:
while not self.__shutdown_request:
# XXX: Consider using another file descriptor or
# connecting to the socket to wake this up instead of
# polling. Polling reduces our responsiveness to a
# shutdown request and wastes cpu at all other times.
try:
r, w, e = select.select([self], [], [], poll_interval)
except select.error as ex:
#print ex
if ex[0] == 4:
continue
else:
raise
if self in r:
self._handle_request_noblock()
finally:
self.__shutdown_request = False
self.__is_shut_down.set()
我只是遇到了一个类似的问题,当我在一个程序中添加了一个小小的httpd服务器时,它接收来自其他进程的各种信号。经过反复研究,我提出了一个简单的解决方案,可以避免实际修改stlib代码,但我认为这有点冒险。我只是将serve_forever调用包装在一个捕捉并忽略套接字错误的循环中:
def non_int_serve_forever(self, poll_interval=0.5):
while 1:
try:
self.serve_forever(poll_interval=poll_interval)
break
except select.error:
pass
这消除了不同版本的SocketServer.py需要不同解决方案的风险,但是serve_forever()是否应该多次重新启动并不明显,即使它现在似乎可以工作
有什么想法吗?代码片段没有太大帮助,因为它不必与您粘贴在下面的堆栈跟踪(也不必调用您提到的
open_file()
有关)。您知道跟踪中提到的select()
调用被什么中断了吗?通常,“中断的系统调用”是一个错误,应该通过重试系统调用来处理。我不清楚select.select()为什么不自己重试。您需要捕获“select.error”,检查其errno属性是否等于errno.EINTR,如果是,则忽略它。