matplot python直方图中缺少最后一个箱子

我正试图根据我的价值来绘制历史记录

x = ['3', '1', '4', '1', '5', '9', '2', '6', '5', '3', '5',
     '2', '3', '4', '5', '6', '4', '2', '0', '1', '9', '8', 
     '8', '8', '8', '8', '9', '3', '8', '0', '9', '5', '2',
     '5', '7', '2', '0', '1', '0', '6', '5']
x_num = [int(i) for i in x]

key = '0123456789'
for i in key:
    print(i," count =>",x.count(i))

plt.hist(x_num, bins=[0,1,2,3,4,5,6,7,8,9])

最后两个数字“8，9”存储箱的分发计数应为6，4 但在直方图中，它将8和9结合起来，得到10的值，而不是将它们分开。垃圾箱的总数应该是10=>但它只给出了9的图表

我怎样才能把它们分开，打破8和9

plt.hist（x_num，箱子=[0,1,2,3,4,5,6,7,8,9,10]）

来自文档：

箱子的边缘。长度nbins+1（nbins最后一个箱子的左边缘和右边缘）

import matplotlib.pyplot as plt


x = ['3', '1', '4', '1', '5', '9', '2', '6', '5', '3', '5',
     '2', '3', '4', '5', '6', '4', '2', '0', '1', '9', '8',
     '8', '8', '8', '8', '9', '3', '8', '0', '9', '5', '2',
     '5', '7', '2', '0', '1', '0', '6', '5']
x_num = [int(i) for i in x]

key = '0123456789'
for i in key:
    print(i, " count =>", x.count(i))

plt.hist(x_num, bins=[0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10])
plt.show()