Python 选择并修改特定文本后的xpath节点

我使用此代码获取所有名称：

def parse_authors(self, root): 
    author_nodes = root.xpath('//a[@class="booklink"][contains(@href,"/author/")]/text()')
    if author_nodes:
        return [unicode(author) for author in author_nodes]

但我想知道，如果有翻译人员在他们的名字旁边加上“（翻译）”：

example:translator1(translation)

---

您可以使用

translation:

text节点来区分作者和翻译人员-作者是“translation:”文本节点的前辈，翻译人员-后辈

作者：

//text()[contains(., 'translation:')]/preceding-sibling::a[@class='booklink' and contains(@href, '/author/')]/text()

//text()[contains(., 'translation:')]/following-sibling::a[@class='booklink' and contains(@href, '/author/')]/text()

翻译人员：

//text()[contains(., 'translation:')]/preceding-sibling::a[@class='booklink' and contains(@href, '/author/')]/text()

//text()[contains(., 'translation:')]/following-sibling::a[@class='booklink' and contains(@href, '/author/')]/text()

工作示例代码：

from lxml.html import fromstring

data = """
<td>
    <a class="booklink" href="/author/43710/Author 1">Author 1</a>
    ,
     <a class="booklink" href="/author/46907/Author 2">Author 2</a>
     <br>
     translation:
     <a class="booklink" href="/author/47669/translator 1">Translator 1</a>
     ,
     <a class="booklink" href="/author/9382/translator 2">Translator 2</a>
</td>"""

root = fromstring(data)

authors = root.xpath("//text()[contains(., 'translation:')]/preceding-sibling::a[@class='booklink' and contains(@href, '/author/')]/text()")
translators = root.xpath("//text()[contains(., 'translation:')]/following-sibling::a[@class='booklink' and contains(@href, '/author/')]/text()")

print(authors)
print(translators)