Python 使用beautifulsoup按正确顺序分析项目符号列表

我正在尝试解析一个网站，它的结构与此非常相似：

<div class="InternaTesto">
<p class="MarginTop0">Paragraph 1</p><br>
<p>Paragraph 2</p><br>
<p><strong>Paragraph 3</strong></p><br>
<ul>
    <li style="margin: 0px; text-indent: 0px;"><em>List item 1</em></li>
    <li style="margin: 0px; text-indent: 0px;"><em>List item 2</em></li>
    <li style="margin: 0px; text-indent: 0px;"><em>List item 3</em></li>
    ... Some Other Items ...
</ul>
<p><strong>Paragraph 4</strong></p><br>
<ul>
    <li style="margin: 0px; text-indent: 0px;"><em>List item 1</em></li>
    <li style="margin: 0px; text-indent: 0px;"><em>List item 2</em></li>
    <li style="margin: 0px; text-indent: 0px;"><em>List item 3</em></li>
    ... Some Other Items ...
</ul>
... Some Other paragraphs ...
</div>

---

有没有办法创建包含所有

项目的子列表或单独列表？
您可以找到所有段落，并为每个段落获得下一个第三个同级：

from bs4 import BeautifulSoup

data = """
Your html here
"""

soup = BeautifulSoup(data)
for p in soup.find('div', attrs={'class':'InternaTesto'}).find_all("p"):
    print p.text, [li.text for li in list(p.next_siblings)[2].find_all('li')]

印刷品：

Paragraph 1 []
Paragraph 2 []
Paragraph 3 [u'List item 1', u'List item 2', u'List item 3']
Paragraph 4 [u'List item 1', u'List item 2', u'List item 3']


更可靠的方法是迭代每个段落的下一个同级，直到找到下一个段落标记：

soup = BeautifulSoup(data)
for p in soup.find('div', attrs={'class':'InternaTesto'}).find_all("p"):
    print p.text
    for sibling in p.next_siblings:
        if sibling.name == 'ul':
            print [li.text for li in sibling.find_all('li')]
        if sibling.name == 'p':
            break

希望有帮助

soup = BeautifulSoup(data)
for p in soup.find('div', attrs={'class':'InternaTesto'}).find_all("p"):
    print p.text
    for sibling in p.next_siblings:
        if sibling.name == 'ul':
            print [li.text for li in sibling.find_all('li')]
        if sibling.name == 'p':
            break