Python 如何为系列中的单元格编制索引?
我用了这个密码Python 如何为系列中的单元格编制索引?,python,jupyter-notebook,Python,Jupyter Notebook,我用了这个密码 nonzero = ucla_all[ucla_all['ADJUSTMENTS']!= 0] cond = (nonzero.groupby(['SERV_CODE', 'CPT_CODE']).mean())['ADJUSTMENTS'] cond 显示此表的步骤 SERV_CODE CPT_CODE 2110 90834 -600.000000 90837 -421.000000 2111 90849
nonzero = ucla_all[ucla_all['ADJUSTMENTS']!= 0]
cond = (nonzero.groupby(['SERV_CODE', 'CPT_CODE']).mean())['ADJUSTMENTS']
cond
显示此表的步骤
SERV_CODE CPT_CODE
2110 90834 -600.000000
90837 -421.000000
2111 90849 -110.000000
90853 -130.000000
2220 90834 -800.000000
90837 -416.534804
90849 -110.000000
如何为第三列编制索引?nonzero=ucla_all[ucla_all['ADJUSTMENTS']!=0]
cond=(非零.groupby(['SERV_CODE','CPT_CODE']).mean())['ADJUSTMENTS']
cond.columns=['SERV_CODE'、'CPT_CODE'、'NEW_COLUMN_NAME']
您可能希望将您的建议编辑到问题的代码段中,以便将来的用户不需要澄清将其放在何处。
SERV_CODE CPT_CODE NEW_COLUMN_NAME
2110 90834 -600.000000
90837 -421.000000
2111 90849 -110.000000
90853 -130.000000
2220 90834 -800.000000
90837 -416.534804
90849 -110.000000