Python 如何对包含数字和字符的字符串列表进行排序
我有Python 如何对包含数字和字符的字符串列表进行排序,python,string,sorting,numbers,character,Python,String,Sorting,Numbers,Character,我有list=['1-10','1-9','1-8','1-11a','1-12','1-11b','1-11'] 应按以下方式进行分类: sortedlist = ['1-8', '1-9', '1-10', '1-11', '1-11a', '1-11b', '1-12']. 我该怎么做 我可以通过split方法分离字符串,只关心-后面的内容 list.sort(key=lambda a: a.split('-')[1]) 但是1-10,1-11等等在1-8之前出现。我不能使用int()
list=['1-10','1-9','1-8','1-11a','1-12','1-11b','1-11']
应按以下方式进行分类:
sortedlist = ['1-8', '1-9', '1-10', '1-11', '1-11a', '1-11b', '1-12'].
我该怎么做
我可以通过split方法分离字符串,只关心-
后面的内容
list.sort(key=lambda a: a.split('-')[1])
但是1-10,1-11等等在1-8之前出现。我不能使用int(),因为'a'和'b'。使用正则表达式
Ex:
import re
l = ['1-10', '1-9', '1-8', '1-11a', '1-12', '1-11b', '1-11']
l.sort(key=lambda a: (int(re.search(r"\-(\d+)[a-z]*", a).group(1)), re.search(r"\-\d+([a-z]*)", a).group(1)))
print(l)
['1-8', '1-9', '1-10', '1-11', '1-11a', '1-11b', '1-12']
['1-8', '1-9', '1-10', '1-11', '1-11a', '1-11b', '1-12']
输出:
import re
l = ['1-10', '1-9', '1-8', '1-11a', '1-12', '1-11b', '1-11']
l.sort(key=lambda a: (int(re.search(r"\-(\d+)[a-z]*", a).group(1)), re.search(r"\-\d+([a-z]*)", a).group(1)))
print(l)
['1-8', '1-9', '1-10', '1-11', '1-11a', '1-11b', '1-12']
['1-8', '1-9', '1-10', '1-11', '1-11a', '1-11b', '1-12']
使用
lambda
中的元组作为key
参数:
import re
lst = ['1-10', '1-9', '1-8', '1-11a', '1-12', '1-11b', '1-11']
lst.sort(key=lambda a: (int(re.search(r'\d+', a.split('-')[1]).group()), len(a)))
print(lst)
# ['1-8', '1-9', '1-10', '1-11', '1-11a', '1-11b', '1-12']
使用
re
模块:
import re
l = ['1-10', '1-9', '1-8', '1-11a', '1-12', '1-11b', '1-11']
j = [l[i[0]]
for i in sorted(
[(i2, *g)
for i2, i in enumerate(l)
for g in re.findall(r'(\d+)-(\d+)(\w?)', i)],
key=lambda k: (int(k[1]), int(k[2]), k[3]))]
print(j)
印刷品: