Python 为什么我在尝试运行我的Twitter天气机器人时会出现此错误

然后我调用reply_to_tweet（），它会搜索并显示tweet，但当它尝试我获得的位置时： TypeError:“bool”对象不可下标

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我对机器人程序和api相当陌生，我正在使用BeautifulSoup、googlesearch和tweepy

看起来你正在尝试对bool函数

startswith（）

，尝试从

tweet\u位置=[I.strip（“#”）中删除
[0]
，如果I.startswith（“#”）中的I.split（）[0]]

请编辑您的帖子，将

获取天气（）的代码添加到
以及
回复到tweet（）
？谢谢您的回答，我尝试了您建议的内容，但出现了一个新错误“TypeError:quote\u from\u bytes（）expected bytes”@J\u Simm请尝试一下
tweet_location=[i.strip（“#”）表示我在tweet.split（）中的位置，如果i.startswith（“#”）表示[0]
谢谢，这很烦人，因为这只是一件小事，但由于某些原因，它不会得到天气，它不会产生错误，只是说“列表索引超出范围”。谢谢你的帮助。你有没有想过为什么会出现这个索引错误？@J_Simm你到底想通过迭代“tweet_location”来提取什么？
def reply_to_tweet():
    print("retrieving and replying to tweets...")
    last_seen_tweet = read_last_seen(FILE_NAME)
    # mentions_timeline() returns a list of 20 most recent mentions
    mentions = api.mentions_timeline(last_seen_tweet, tweet_mode="extended")

    # reversing to read old tweets first
    for mention in reversed(mentions):
        print(str(mention.id) + " - " + mention.full_text)
        last_seen_tweet = mention.id
        store_last_seen(FILE_NAME, last_seen_tweet)
        if "#" in mention.full_text.lower():
            print("found #")

            location = get_location(mention.full_text)
            weather = get_weather(location)

            # responding to tweet mention
            api.update_status("@" + mention.user.screen_name + weather, mention.id)

def get_location(tweet):
    # takes tweet and returns only the substring attached to hashtag
    tweet_location = [i.strip("#") for i in tweet.split() if i.startswith("#")[0]]
    tweet_location += " today weather.com"
    return tweet_location

def get_weather(query):
    for url in search(query, stop=1):
        print("Results is " + url)

    #this code sends a request and reads the webpage enclsed to the request
    request = Request(url, headers={"User-Agent": "Mozilla/5.0"})

    webpage = urlopen(request).read()
    soup = BeautifulSoup(webpage, "html.parser")

    try:
        title = soup.findAll("span", "today-daypart-title")[0].string 
        phrase = soup.findAll("span", "today-daypart-wxphrase")[0].string
    except IndexError as e:
        forecast = (" could not find the weather, check back later")
        print(e)
    else:
        forecast = (" forecast for " + title + " is " + phrase)
        print(forecast)

    return forecast

while True:
    reply_to_tweet()
    time.sleep(15)