为mp3曲目编号时，仅在某些文件上出现此python脚本错误
这是我做的一个脚本，将曲目编号放在MP3名称之前，以保持曲目的正确顺序，而不是按字母顺序排列 除了三个文件夹外，它在所有文件夹（100多个文件夹/1300多首歌曲）上都运行良好 我不知道世跆拳道在这里发生了什么 有人有什么想法吗为mp3曲目编号时，仅在某些文件上出现此python脚本错误,python,mutagen,windowserror,Python,Mutagen,Windowserror,这是我做的一个脚本，将曲目编号放在MP3名称之前，以保持曲目的正确顺序，而不是按字母顺序排列 除了三个文件夹外，它在所有文件夹（100多个文件夹/1300多首歌曲）上都运行良好 我不知道世跆拳道在这里发生了什么 有人有什么想法吗 output => 输入音乐文件的路径：/n>c:\test path_name=c:\test\2-Live Albums\1995-MTV未插拔\Shooting Star.mp3 02-Shooting Star.mp3 path_name=c:\tes
output =>
#!usr/bin/env python
__author__ = 'Brian Kane'
"""This scripts takes a path argument to the root directory of the music files (mp3 here) and
adds a padded number corresponding to the track number. It will do this to all of the tracks in the folders
and subfolders. This allows for burning in the track order and not alphabetized. In theory I suppose you could
start at C:'\'"""
import os
from os.path import *
import string
from mutagen.mp3 import MP3
from mutagen.easyid3 import EasyID3
def music_track_numbering(path):
nums = []
for i in range(10): # just fills in nums to compare to track name
# to not double number
nums.append(str(i))
for root, dirs, files in os.walk(path): # walks through the data tree to get files
# print 'root = ', root
# print 'dirs = ', dirs
# print 'files = ',files
for name in files:
extension = os.path.splitext(name)[1][1:].strip().lower() # gets the file extension
if name[0] in nums: # don't double number
break
if extension == 'mp3':
# print 'name = ', name # test purposes
path_name = root +'\\' + name # path_name is complete path
print 'path_name = ', path_name # test purposes
track = EasyID3(path_name)['tracknumber'][0] # gets the track number from metadata
track_number = str(track).zfill(2) + ' - ' + name # pads leading zero and adds dash to name
os.rename(join(root,name),join(root,track_number)) # renames the file
print track_number # test purposes
# path = 'C:\\test' # this is a test path
path = raw_input('Enter the path to the music file:/n>')
music_track_numbering(path)
没有什么明显的东西向我扑来。在
os.rename（）