总结python输出中显示的字符串总数

总结python输出中显示的字符串总数,python,log-analysis,Python,Log Analysis,例如,我想显示Dest端口号53出现了多少次,并且日志文件中有2000个数据,所以我需要显示每个Dest端口的总和。这是我的代码: def main(): f = openfile("/Users/rin/Desktop/new sec/2017-04-18_010.082.012.003.txt") if f is None: print("File not found") return s = splitline(f) for

例如,我想显示Dest端口号53出现了多少次,并且日志文件中有2000个数据,所以我需要显示每个Dest端口的总和。这是我的代码:

def main():
    f = openfile("/Users/rin/Desktop/new sec/2017-04-18_010.082.012.003.txt")
    if f is None:
        print("File not found")
        return
    s = splitline(f)
    for el in s:
        if len(el) > 50:
            p = parselog(el)
            if "dstport" in p:

             print("Dest Port : %s" % p["dstport"])
             if "app" in p:
                 print("Apps : %s" % p["app"])
            print("")
输出:

Dest Port : 53
Apps : DNS

Dest Port : 123
Apps : NTP

Dest Port : 53
Apps : DNS

Dest Port : 53
Apps : DNS

就像我有2000个这样的端口,那么我怎样才能一个接一个地进行输出呢?@warezers更新了,但不确定python3的语法
def main():
    f = openfile("/Users/rin/Desktop/new sec/2017-04-18_010.082.012.003.txt")
    if f is None:
        print("File not found")
        return
    s = splitline(f)

    # add a counter
    counts = {}

    for el in s:
        if len(el) > 50:
             p = parselog(el)

             if "dstport" in p:
                 # increment counter
                 if p["dstport"] in counts:
                     counts[str(p["dstport"])] += 1
                 else:
                     counts[str(p["dstport"])] = 1
                 print("Dest Port : %s" % p["dstport"])
             if "app" in p:
                 print("Apps : %s" % p["app"])
             print("")

    # output the count
    for k, v in counts.iteritems():
         print 'Dest Port %s Count: %s' % (k, v)