Python 如何同时检查一个范围内的两个值？

我想用一行代码检查它们。可能吗？否则，我目前拥有的代码是：

while True:
    player_number = int(input('Determine first player Random(0) or AI(1):'))
    player_number2 = int(input('Determine second player Random (0) or AI (1):'))

    if player_number, player_number2 in range(0,2): # shows error
        break
    else:
        print ('Out of range. Please choose a player')

---

我会使用

和
：

if player_number in (0, 1) and player_number2 in (0, 1):

您也可以使用集合，但不太清楚：

if {player_number, player_number2} <= {0, 1}:

如果{player\u number，player\u number2}我只会使用
和
：

if player_number in (0, 1) and player_number2 in (0, 1):

您也可以使用集合，但不太清楚：

if {player_number, player_number2} <= {0, 1}:

如果{player\u number，player\u number2}您可以使用
all
语句：

if all(i in range(0, 2) for i in (player_number, player_number2)):

这种方法的好处是它很容易扩展到多个玩家

更好的选择是使用字典并与集合进行比较：

while True:
    players = {k: int(input('Determine player {0} Random(0) or AI(1):'.format(k)))\
                  for k in range(0, 2)}
    if set(players.values()) <= {0, 1}:
        break
else:
    print('Out of range. Please choose a player')

为True时：
players={k:int（输入（'determinate player{0}Random（0）或AI（1）：'）。格式（k）））\
对于范围（0，2）}
如果设置了（players.values（）），则可以使用
all
语句：

if all(i in range(0, 2) for i in (player_number, player_number2)):

这种方法的好处是它很容易扩展到多个玩家

更好的选择是使用字典并与集合进行比较：

while True:
    players = {k: int(input('Determine player {0} Random(0) or AI(1):'.format(k)))\
                  for k in range(0, 2)}
    if set(players.values()) <= {0, 1}:
        break
else:
    print('Out of range. Please choose a player')

为True时：
players={k:int（输入（'determinate player{0}Random（0）或AI（1）：'）。格式（k）））\
对于范围（0，2）}
如果设置（players.values（））