如何为python更改此公式?新手到编码,任何帮助是感激的
您好,我目前已从网上获得此代码。它当前获取以下股票的url和公司信息。有没有办法更新此代码,以显示行业和行业信息来代替url和公司信息?新手编程,因此希望您能提供帮助:) 代码如下:如何为python更改此公式?新手到编码,任何帮助是感激的,python,yahoo-finance,Python,Yahoo Finance,您好,我目前已从网上获得此代码。它当前获取以下股票的url和公司信息。有没有办法更新此代码,以显示行业和行业信息来代替url和公司信息?新手编程,因此希望您能提供帮助:) 代码如下: import bs4 as BeautifulSoup from bs4 import SoupStrainer import re import urllib.request import pandas as pd import requests symbols = ['SBUX', 'MET', 'CAT
import bs4 as BeautifulSoup
from bs4 import SoupStrainer
import re
import urllib.request
import pandas as pd
import requests
symbols = ['SBUX', 'MET', 'CAT', 'JNJ', 'ORCL']
headers = {'User-agent': 'Mozilla/5.0'}
mySymbols = {}
for s in symbols:
vals = {}
url = ("https://finance.yahoo.com/quote/{}/profile?p={}".format(s,s))
webpage = requests.get(url, headers=headers)
soup = BeautifulSoup.BeautifulSoup(webpage.content)
title = soup.find("title")
tmp = title.get_text()
rxTitle = re.compile(r'\(.*$')
coName = rxTitle.sub("", tmp)
for link in soup.find_all('a', href=True):
try:
if link['target'] and "" == link['title']:
m = re.search('yahoo', link['href'], flags=re.IGNORECASE)
if None == m:
url = link['href']
webpage = requests.get(url, headers=headers)
soup = BeautifulSoup.BeautifulSoup(webpage.content)
vals = {"company":coName, "url":link['href']}
print (s, vals)
mySymbols[s] = vals
except:
pass
查看其中一个页面,我看到该行业的跨度为'class'='Fw(600)'和'data reactid'=21,行业的跨度为data reactid=25,因此您可以使用
sector = soup.find('span', {'class':'Fw(600)','data-reactid': '21'})
print(sector.next)
industry = soup.find('span', {'class':'Fw(600)','data-reactid': '25'})
print(industry.next)
sector.next获取范围内的内容,而不是返回整个内容
查找“部门”和“行业”跨度并返回后续跨度的更好方法完全编码如下:
import bs4 as BeautifulSoup
import requests
def get_tags(url):
webpage = requests.get(url, headers=headers)
soup = BeautifulSoup.BeautifulSoup(webpage.content)
title = soup.find("title")
results = {}
tmp = title.get_text()
results['title'] = tmp
spans = soup.findAll('span')
for i in range(len(spans)):
if spans[i] and spans[i].text == 'Sector':
sector = spans[i+1].text
results['Sector'] = sector
if spans[i] and spans[i].text == 'Industry':
industry = spans[i+1].text
results['Industry'] = industry
return results
headers = {'User-agent': 'Mozilla/5.0'}
symbols = ['SBUX', 'MET', 'CAT', 'JNJ', 'ORCL']
for s in symbols:
url = ("https://finance.yahoo.com/quote/{}/profile?p={}".format(s,s))
results = get_tags(url)
print(results)
显示的代码缩进不一致。我不确定它应该是什么,所以我不能尝试编辑它,但是如果你可以的话,它会有帮助的。我现在就编辑它。谢谢你的帮助!嘿,如果你能澄清我如何使用它,我将不胜感激。例如,在我的情况下,我应该改变哪些方面?非常感谢。非常感谢你的帮助!非常感谢!另一个问题是,如何更改结果以显示为数据帧?再次感谢