在其他列表中迭代python列表

我在两个列表之间进行迭代以查看其中一个列表是否包含另一个列表的元素时遇到了问题。在其中一个列表中，我有另一个列表。有时此列表仅包含字符串，有时包含字符串和。。另一份名单

这就是问题所在。如果它只有字符串，我想知道那些字符串中的

是否都在
Mainlist
中

但是，如果我有srtings
和
另一个列表。。我想知道列表外的所有字符串是否都在
Mainlist
中，列表内的至少一个字符串是否在
Mainlist
中


假设我有一个主要列表：
Mainlist=['AA'，'BB'，'CC'，'DD'，'EE'，'FF']

现在，我有另外一个列表，我想在这个
Mainlist
上迭代：

list1=[['AA'、['BB'、['YY']]、['AA'、['GG']]]

在
list1
上，我有两个列表：
['AA'，['BB'，'YY']]
和
['AA'，'GG']
一个只有字符串，另一个有字符串和另一个列表

现在我需要知道
list1
上的元素是否在
Mainlist
上，并获取
list1
上的元素的索引，这些元素给出了
True
结果

在这种情况下，在
索引0
处应该是
True
。因为
Mainlist
中有
'AA'
和
'BB'
项


其他例子：

list2 = [['AA', 'JJ'], ['EE', 'FF']] # False at index 0 = Mainlist does not have 'JJ' / True at index 1 = Mainlist has 'EE' and 'FF'
list3 = [['AA', 'KK', ['BB', 'CC']], ['JJ', 'GG']] # False at index 0 item 'KK' is not in Mainlist / False at index 1 = Mainlist does not have 'JJ' and 'GG'
list4 = [['EE', 'FF', "OO"], ['AA', 'BB', 'CC',['DD', 'MM']], ['GG', ['BB', 'CC', 'DD']]] #False at index 0 = Mainlist does not have 'OO' / True at index 1  = Even if 'MM' is not in Mainlist, 'DD' is. / False  at index 2 = 'GG' is not in Mainlist

为了达到这个目的，我头疼。。有没有人能给我一个提示？
提前感谢
这应该可以。您可以在注释中找到解释：

list1 = [['AA', ['BB', 'YY']], ['AA', 'GG']]  # True, False
list2 = [['AA', 'JJ'], ['EE', 'FF']]  # False at index 0 = Mainlist does not have 'JJ' / True at index 1 = Mainlist has 'EE' and 'FF'
list3 = [['AA', 'KK', ['BB', 'CC']], ['JJ', 'GG']]  # False at index 0 item 'KK' is not in Mainlist / False at index 1 = Mainlist does not have 'JJ' and 'GG'
list4 = [['EE', 'FF', "OO"], ['AA', 'BB', 'CC', ['DD', 'MM']], ['GG', ['BB', 'CC', 'DD']]]  # False at index 0 = Mainlist does not have 'OO' / True at index 1  = Even if 'MM' is not in Mainlist, 'DD' is. / False  at index 2 = 'GG' is not in Mainlist

Mainlist = ['AA', 'BB', 'CC', 'DD', 'EE', 'FF']


def eval_list(lst):
    r = []
    for sublist in lst:
        if all(isinstance(i, str) for i in sublist):       # if everything is str
            r.append(all(i in Mainlist for i in sublist))  # check if all of them in Mainlist
        else:                                              # else
            r.append(
                all(isinstance(item, str) and item in Mainlist # check if item is in Mainlist if it is str
                    or                                         # or 
                    any(i in Mainlist for i in item)           # check any i in item is in Mainlist
                        for item in sublist)                   # for every item in sublist
                )

    return r

for lst in [list1, list2, list3, list4]:
    print(eval_list(lst))


您可以尝试这样做，返回一个包含每个索引及其相应布尔值的字典：

list2 = [['AA', 'JJ'], ['EE', 'FF']] # False at index 0 = Mainlist does not have 'JJ' / True at index 1 = Mainlist has 'EE' and 'FF'
list3 = [['AA', 'KK', ['BB', 'CC']], ['JJ', 'GG']] # False at index 0 item 'KK' is not in Mainlist / False at index 1 = Mainlist does not have 'JJ' and 'GG'
list4 = [['EE', 'FF', "OO"], ['AA', 'BB', 'CC',['DD', 'MM']], ['GG', ['BB', 'CC', 'DD']]] #False at index 0 = Mainlist 
Mainlist = ['AA', 'BB', 'CC', 'DD', 'EE', 'FF']


def func(ls):
    dct={}
    for idx,l in enumerate(ls):
        if all(isinstance(elem, str) for elem in l):
            dct.update({idx:all(elem in Mainlist for elem in l)})
        else:
            cond=all(el in Mainlist for el in [i for i in l if isinstance(i, str)]) and any(ele in Mainlist for el in [i for i in l if isinstance(i, list)] for ele in el)
            dct.update({idx:cond})
    return dct

print(func(list2))
print(func(list3))
print(func(list4))

输出：

{0: False, 1: True}
{0: False, 1: False}
{0: False, 1: True, 2: False}

你提到：1。当列表仅包含字符串2时所需的内容。当列表包含字符串和其他列表时所需的内容。当它只有其他列表时，期望得到什么？
{0: False, 1: True}
{0: False, 1: False}
{0: False, 1: True, 2: False}