如何从内部完全重新启动python脚本？

我正在创建一个小计算器作为一个项目，我希望它在完成后键入yes时重新启动。问题是，我似乎不知道怎么做。说到python，我不是一个天才

   import sys

    OPTIONS = ["Divide", "divide", "Multiply", "multiply", "Add", "add", "Subtract", "subtract"]

    def userinput():
        while True:
            try:

                number = int(input("Number: "))
                break
            except ValueError:
                print("NOPE...")
        return number

    def operation():
        while True:
            operation = input("Multiply/Divide/Add: ")
            if operation in OPTIONS:
                break
            else:
                print("Not an option.")
        return operation

    def playagain():
        while True:
            again = input("Again? Yes/No: ")
            if again == "Yes" or again == "yes":
                 break
            elif again == "No" or again == "no":
                sys.exit(0)
            else:
                print("Nope..")

    def multiply(x,y):
        z = x * y
        print(z)

    def divide(x,y):
        z = x / y
        print(z)

    def add(x,y):
        z = x + y
        print(z)

    def subtract(x,y):
        z = x - y
        print(z)

    while True:

        operation = operation()
        x = userinput()
        y = userinput()
        if operation == "add" or operation == "Add":
            add(x,y)
        elif operation == "divide" or operation == "Divide":
            divide(x,y)
        elif operation == "multiply" or operation == "Multiply":
            multiply(x,y)
        elif operation == "subtract" or operation == "Subtract":
            subtract(x,y)

        playagain()

我目前在第28行有一个中断，因为我不知道如何重新启动它。如果有人能帮我，谢谢

使用os.execv（）

---

您不需要重新启动脚本，只需在编写代码之前考虑一下设计。根据您提供的脚本，此问题有两种修改：

def playagain():

    while True:
        again = input("Again? Yes/No: ")
        if again == "Yes" or again == "yes":
             return True
        elif again == "No" or again == "no":
             return False
        else:
            print("Nope..")

然后，在调用

playreach（）

的地方，将其更改为：

if not playagain(): break

我想我知道你为什么要重新启动脚本，你有一个bug

Python函数与任何其他对象类似。当你说：

operation = operation()  

将对

操作的引用

函数重新分配给该函数返回的字符串。因此，在重新启动时第二次调用时，它会失败：

TypeError: 'str' object is not callable

将

操作

函数重命名为类似

fooperation

：

def fopertion():

然后：

因此，完整的代码变成：

import sys

OPTIONS = ["Divide", "divide", "Multiply", "multiply", "Add", "add", "Subtract", "subtract"]

def userinput():
    while True:
        try:

            number = int(input("Number: "))
            break
        except ValueError:
            print("NOPE...")
    return number

def foperation():
    while True:
        operation = input("Multiply/Divide/Add: ")
        if operation in OPTIONS:
            break
        else:
            print("Not an option.")
    return operation


def playagain():

    while True:
        again = input("Again? Yes/No: ")
        if again == "Yes" or again == "yes":
             return True
        elif again == "No" or again == "no":
             return False
        else:
            print("Nope..")

def multiply(x,y):
    z = x * y
    print(z)

def divide(x,y):
    z = x / y
    print(z)

def add(x,y):
    z = x + y
    print(z)

def subtract(x,y):
    z = x - y
    print(z)

while True:

    operation = foperation()
    x = userinput()
    y = userinput()
    if operation == "add" or operation == "Add":
        add(x,y)
    elif operation == "divide" or operation == "Divide":
        divide(x,y)
    elif operation == "multiply" or operation == "Multiply":
        multiply(x,y)
    elif operation == "subtract" or operation == "Subtract":
        subtract(x,y)

    if not playagain(): break

---

我还可以对这段代码做很多其他的改进，但是让我们先让它工作起来。

我没有重新启动scrip，而是让你可以永远使用它，只有用户自己可以退出它。最后，我只更改了playreach（）和while循环，请阅读注释以获得解释：

import sys

OPTIONS = ["Divide", "divide", "Multiply", "multiply", "Add", "add", "Subtract", "subtract"]

# python2 compatibility, you dont need to care about this ;-)
try:
    input = raw_input
except:
    pass

def userinput():
    while True:
        try:

            number = int(input("Number: "))
            break
        except ValueError:
            print("NOPE...")
    return number

def operation():
    while True:
        operation = input("Multiply/Divide/Add: ")
        if operation in OPTIONS:
            break
        else:
            print("Not an option.")
    return operation

def playagain():
    """
    return True if userinput "Yes" and False if userinput "no"
    does this until user input is yes or no
    """
    again = input("Again? Yes/No: ")
    if again.lower() == "yes":
        return True
    elif again.lower() == "no":
        return False
    else:
        # reruns the code --> until user input is 'yes' or 'no'
        return playagain()

def multiply(x,y):
    z = x * y
    print(z)

def divide(x,y):
    z = x / y
    print(z)

def add(x,y):
    z = x + y
    print(z)

def subtract(x,y):
    z = x - y
    print(z)

# a main in python: this will be executed when run as a script
# but not when you import something from this
if __name__ == '__main__':

    play = True
    while play:
        operation = operation()
        x = userinput()
        y = userinput()
        if operation == "add" or operation == "Add":
            add(x,y)
        elif operation == "divide" or operation == "Divide":
            divide(x,y)
        elif operation == "multiply" or operation == "Multiply":
            multiply(x,y)
        elif operation == "subtract" or operation == "Subtract":
            subtract(x,y)

        # player/user can exit the loop if he enters "no" and therefore end the loop
        play = playagain()

---

请在问题本身中添加一个，而不是指向其他地方所有代码的链接。同时，通常的答案是：将所有顶级代码封装在函数中，然后在

中调用该函数，而True:

循环。这在某些情况下不起作用（例如，如果你有一堆混乱的全球状态），但是试试看，看看你是否能让它起作用。对不起！我是新来的。我该怎么做？我有这个。def playreach（）：while True:reach=input（“reach？Yes/No:”）if reach==“Yes”或reach==“Yes”：再次中断elif==“No”或reach==“No”：sys.exit（0）else:print（“Nope..”），就像我说的，我不是什么天才。所以我对你刚才说的几乎一无所知。不过我学得很快：另一方面，如果你了解字典，你可以把函数放在字典里，比如。或者甚至变得很棘手，比如说，它说它与任何“缩进”级别都不匹配。

import sys

OPTIONS = ["Divide", "divide", "Multiply", "multiply", "Add", "add", "Subtract", "subtract"]

# python2 compatibility, you dont need to care about this ;-)
try:
    input = raw_input
except:
    pass

def userinput():
    while True:
        try:

            number = int(input("Number: "))
            break
        except ValueError:
            print("NOPE...")
    return number

def operation():
    while True:
        operation = input("Multiply/Divide/Add: ")
        if operation in OPTIONS:
            break
        else:
            print("Not an option.")
    return operation

def playagain():
    """
    return True if userinput "Yes" and False if userinput "no"
    does this until user input is yes or no
    """
    again = input("Again? Yes/No: ")
    if again.lower() == "yes":
        return True
    elif again.lower() == "no":
        return False
    else:
        # reruns the code --> until user input is 'yes' or 'no'
        return playagain()

def multiply(x,y):
    z = x * y
    print(z)

def divide(x,y):
    z = x / y
    print(z)

def add(x,y):
    z = x + y
    print(z)

def subtract(x,y):
    z = x - y
    print(z)

# a main in python: this will be executed when run as a script
# but not when you import something from this
if __name__ == '__main__':

    play = True
    while play:
        operation = operation()
        x = userinput()
        y = userinput()
        if operation == "add" or operation == "Add":
            add(x,y)
        elif operation == "divide" or operation == "Divide":
            divide(x,y)
        elif operation == "multiply" or operation == "Multiply":
            multiply(x,y)
        elif operation == "subtract" or operation == "Subtract":
            subtract(x,y)

        # player/user can exit the loop if he enters "no" and therefore end the loop
        play = playagain()