Python:单击鼠标返回坐标信息
我想用python显示一个图像,并允许用户点击一个特定的像素。然后我想使用x和y坐标来执行进一步的计算 到目前为止,我一直在使用事件选择器:Python:单击鼠标返回坐标信息,python,matplotlib,user-interaction,Python,Matplotlib,User Interaction,我想用python显示一个图像,并允许用户点击一个特定的像素。然后我想使用x和y坐标来执行进一步的计算 到目前为止,我一直在使用事件选择器: def onpick1(event): artist = event.artist if isinstance(artist, AxesImage): mouseevent = event.mouseevent x = mouseevent.xdata y = mouseevent.ydata
def onpick1(event):
artist = event.artist
if isinstance(artist, AxesImage):
mouseevent = event.mouseevent
x = mouseevent.xdata
y = mouseevent.ydata
print x,y
xaxis = frame.shape[1]
yaxis = frame.shape[0]
fig = plt.figure(figsize=(6,9))
ax = fig.add_subplot(111)
line, = [ax.imshow(frame[::-1,:], cmap='jet', extent=(0,xaxis,0,yaxis), picker=5)]
fig.canvas.mpl_connect('pick_event', onpick1)
plt.show()
现在我非常希望函数onpick1()返回x和y,这样我可以在plt.show()之后使用它来执行进一步的计算
有什么建议吗?GUI编程的一个很好的教训是面向对象。现在的问题是,您有一个异步回调,并且希望保留其值。你应该考虑把所有东西打包在一起,比如:
class MyClickableImage(object):
def __init__(self,frame):
self.x = None
self.y = None
self.frame = frame
self.fig = plt.figure(figsize=(6,9))
self.ax = self.fig.add_subplot(111)
xaxis = self.frame.shape[1]
yaxis = self.frame.shape[0]
self.im = ax.imshow(self.frame[::-1,:],
cmap='jet', extent=(0,xaxis,0,yaxis),
picker=5)
self.fig.canvas.mpl_connect('pick_event', self.onpick1)
plt.show()
# some other associated methods go here...
def onpick1(self,event):
artist = event.artist
if isinstance(artist, AxesImage):
mouseevent = event.mouseevent
self.x = mouseevent.xdata
self.y = mouseevent.ydata
现在,当您单击一个点时,它将设置类的x
和y
属性。但是,如果要使用x
和y
执行计算,只需使用onpick1
方法执行这些计算即可