Python 返回特定列的值为空的df

我正在从SQL代码移动到python，我有一个

WHERE

条件，说WHERE points是

NULL

我需要打印我的dataframe，data，这样有问题的一列points就包含了所有Null

例如

我希望它能退回这个：

name:    age:
Jack     14
David    16
Paul     15

---

如果需要筛选值

0

，请使用

布尔索引

df = pd.DataFrame({'points': {0: 3, 1: 0, 2: 2, 3: 0, 4: 0}, 
                   'name': {0: 'Sean', 1: 'Jack', 2: 'Peter', 3: 'David', 4: 'Paul'},
                   'age': {0: 12, 1: 14, 2: 11, 3: 16, 4: 15}})    
print (df)
   age   name  points
0   12   Sean       3
1   14   Jack       0
2   11  Peter       2
3   16  David       0
4   15   Paul       0

df1 = df.ix[df.points == 0,['name','age']]
print (df1)
    name  age
1   Jack   14
3  David   16
4   Paul   15

如果值为

NaN

：

df = pd.DataFrame({'points': {0: 3, 1: np.nan, 2: 2, 3: np.nan, 4: np.nan}, 
                   'name': {0: 'Sean', 1: 'Jack', 2: 'Peter', 3: 'David', 4: 'Paul'},
                   'age': {0: 12, 1: 14, 2: 11, 3: 16, 4: 15}})    
print (df)
   age   name  points
0   12   Sean     3.0
1   14   Jack     NaN
2   11  Peter     2.0
3   16  David     NaN
4   15   Paul     NaN

df1 = df.ix[df.points.isnull(),['name','age']]
print (df1)
    name  age
1   Jack   14
3  David   16
4   Paul   15

---

请检查编辑，我添加了通过

0

和

NaN

过滤的解决方案。

df = pd.DataFrame({'points': {0: 3, 1: np.nan, 2: 2, 3: np.nan, 4: np.nan}, 
                   'name': {0: 'Sean', 1: 'Jack', 2: 'Peter', 3: 'David', 4: 'Paul'},
                   'age': {0: 12, 1: 14, 2: 11, 3: 16, 4: 15}})    
print (df)
   age   name  points
0   12   Sean     3.0
1   14   Jack     NaN
2   11  Peter     2.0
3   16  David     NaN
4   15   Paul     NaN

df1 = df.ix[df.points.isnull(),['name','age']]
print (df1)
    name  age
1   Jack   14
3  David   16
4   Paul   15