Python 将整数赋给列表

我正试图询问用户：
如果他们得了A，询问他们是想要1还是11。 它们回答一个整数，它意味着将其设置为1或11。不幸的是，当我运行时，它仍然是王牌

import time
import random
from random import *

suits = ["Hearts","Diamonds","Clubs","Spades"]
cards = ["Ace","2","3","4","5","6","7","8","9","10","Jack","Queen","King"]

def drawcard():
    global newcardtype
    global newcardsuit
    global newcard
    newcardtype = cards[randint(0,11)] ##User interface & Console
    newcardsuit = suits[randint(0,3)] ##User interface & Console
    newcard = newcardtype, newcardsuit ##Console to read and understand
    print("You picked up: " + str(newcardtype) + " of " + str(newcardsuit) + ".")

suits[0] = "♡"
suits[1] = "♢"
suits[2] = "♧"
suits[3] = "♤"    

cards[10] = 10
cards[11] = 10
cards[12] = 10

while(True):
    test = input("New card? ")
    if test == "y":
        drawcard()
        if newcardtype == cards[0]:
            acequestion = int(input("You picked up an Ace. Would you like your Ace to be 1 or 11?: "))
            if acequestion == 1:
                cards[0] = int(1)
            if acequestion == 11:
                cards[0] = int(11)
        print(newcardtype)

---

它处于工作状态，但我希望

cards[0]

根据“acequestion”问题的答案，“ace”等于1或11。

您将数字1或11分配给

cards[0]

，但这不会改变

newcardtype

引用的对象或值，因此它仍然具有值

'ace'

。如果要更改

newcardtype

的值，还必须为其指定1或11。

int（1）

？？“杀伤力太大了。”让·弗朗索瓦·法布可能是这样，但我想安全，而不是后悔。我是python新手，我想确保它能正常工作，这样我就不会对Ned Batcheld的演讲感到困惑。