Python-VTK:直接坐标到PolyData
我想使用步骤1将特定范围内x、y和z的所有坐标组合直接转换为vtk.polyData或vtk.points。我的第一种方法是使用itertools.product,但我认为这会有一个非常糟糕的运行时。所以我用vtk找到了另一种方法,我的程序的下一部分需要它 第一次使用itertools.product进行评估Python-VTK:直接坐标到PolyData,python,numpy,vtk,Python,Numpy,Vtk,我想使用步骤1将特定范围内x、y和z的所有坐标组合直接转换为vtk.polyData或vtk.points。我的第一种方法是使用itertools.product,但我认为这会有一个非常糟糕的运行时。所以我用vtk找到了另一种方法,我的程序的下一部分需要它 第一次使用itertools.product进行评估 import numpy as np import itertools import vtk x1=[10,11,12....310] y1=[10,11,12....310] z1=[
import numpy as np
import itertools
import vtk
x1=[10,11,12....310]
y1=[10,11,12....310]
z1=[0,1,2....65]
points1 = vtk.vtkPoints()
for coords in itertools.product(x1,y1,z1):
points1.InsertNextPoint(coords)
boxPolyData1 = vtk.vtkPolyData()
boxPolyData1.SetPoints(points1)
迄今为止我对vtk的做法:
import numpy as np
from vtk.util import numpy_support
coords = np.mgrid[10:310, 10:310, 0:65]
vtk_data_array = numpy_support.numpy_to_vtk(num_array=coords.ravel(),deep=True,array_type=vtk.VTK_FLOAT)
points = vtk.vtkPoints()
points.SetData(vtk_data_array)
但是他的话让我的python崩溃了。有人有主意吗
致以最良好的祝愿 将那些
coords
堆叠在带有或的列中,然后将它们作为输入馈送到num\u数组中,如下所示-
x,y,z = np.mgrid[10:310, 10:310, 0:65]
out_data = np.column_stack((x.ravel(), y.ravel(), z.ravel()))
vtk_data_array = numpy_support.numpy_to_vtk(num_array=out_data,\
deep=True,array_type=vtk.VTK_FLOAT)
def create_mgrid_array(d00,d01,d10,d11,d20,d21,dtype=int):
df0 = d01-d00
df1 = d11-d10
df2 = d21-d20
a = np.zeros((df0,df1,df2,3),dtype=dtype)
X,Y,Z = np.ogrid[d00:d01,d10:d11,d20:d21]
a[:,:,:,2] = Z
a[:,:,:,1] = Y
a[:,:,:,0] = X
a.shape = (-1,3)
return a
或者,直接获取数据
-
out_data = np.mgrid[10:310, 10:310, 0:65].reshape(3,-1).T
使用initialization
替换np.mgrid
创建的3D
数组的另一种方法如下-
x,y,z = np.mgrid[10:310, 10:310, 0:65]
out_data = np.column_stack((x.ravel(), y.ravel(), z.ravel()))
vtk_data_array = numpy_support.numpy_to_vtk(num_array=out_data,\
deep=True,array_type=vtk.VTK_FLOAT)
def create_mgrid_array(d00,d01,d10,d11,d20,d21,dtype=int):
df0 = d01-d00
df1 = d11-d10
df2 = d21-d20
a = np.zeros((df0,df1,df2,3),dtype=dtype)
X,Y,Z = np.ogrid[d00:d01,d10:d11,d20:d21]
a[:,:,:,2] = Z
a[:,:,:,1] = Y
a[:,:,:,0] = X
a.shape = (-1,3)
return a
示例运行以展示创建\u mgrid\u数组的用法-
In [151]: create_mgrid_array(3,6,10,14,20,22,dtype=int)
Out[151]:
array([[ 3, 10, 20],
[ 3, 10, 21],
[ 3, 11, 20],
[ 3, 11, 21],
[ 3, 12, 20],
[ 3, 12, 21],
[ 3, 13, 20],
[ 3, 13, 21],
[ 4, 10, 20],
[ 4, 10, 21],
[ 4, 11, 20],
[ 4, 11, 21],
[ 4, 12, 20],
[ 4, 12, 21],
[ 4, 13, 20],
[ 4, 13, 21],
[ 5, 10, 20],
[ 5, 10, 21],
[ 5, 11, 20],
[ 5, 11, 21],
[ 5, 12, 20],
[ 5, 12, 21],
[ 5, 13, 20],
[ 5, 13, 21]])
运行时测试
import numpy as np
import itertools
import vtk
x1=[10,11,12....310]
y1=[10,11,12....310]
z1=[0,1,2....65]
points1 = vtk.vtkPoints()
for coords in itertools.product(x1,y1,z1):
points1.InsertNextPoint(coords)
boxPolyData1 = vtk.vtkPolyData()
boxPolyData1.SetPoints(points1)
接近-
def loopy_app():
x1 = range(10,311)
y1 = range(10,311)
z1 = range(0,66)
points1 = vtk.vtkPoints()
for coords in itertools.product(x1,y1,z1):
points1.InsertNextPoint(coords)
return points1
def vectorized_app():
out_data = create_mgrid_array(10,311,10,311,0,66,dtype=float)
vtk_data_array = numpy_support.numpy_to_vtk(num_array=out_data,\
deep=True,array_type=vtk.VTK_FLOAT)
points2 = vtk.vtkPoints()
points2.SetData(vtk_data_array)
return points2
时间安排和核查-
In [155]: # Verify outputs with loopy and vectorized approaches
...: out1 = vtk_to_numpy(loopy_app().GetData())
...: out2 = vtk_to_numpy(vectorized_app().GetData())
...: print np.allclose(out1, out2)
...:
True
In [156]: %timeit loopy_app()
1 loops, best of 3: 923 ms per loop
In [157]: %timeit vectorized_app()
10 loops, best of 3: 67.3 ms per loop
In [158]: 923/67.3
Out[158]: 13.714710252600298
13x+
在循环的基础上,使用建议的矢量化方法加速 谢谢:),但现在我得到了错误:AssertionError:只支持连续数组:(@Varlor Useout\u data=np.ascontiguousarray(out\u data)
,然后馈送到numpy\u-to\u-vtk
?很好,非常感谢,它可以工作。但不幸的是,它没有对itertools的运行时改进。产品:(@Varlor使用新的基于初始化的方法检查编辑,显示13x+
加速。