Python 无法让脚本向右滑动按钮

Python 无法让脚本向右滑动按钮,python,python-3.x,selenium,selenium-webdriver,web-scraping,Python,Python 3.x,Selenium,Selenium Webdriver,Web Scraping,我已经用python和selenium编写了一个脚本来登录网站。问题是我的脚本有时会成功登录,但大多数情况下它会遇到一个滑块,该滑块用于按下并向右滑动 该滑块的图像: 如何让脚本向右滑动该按钮? 我试过: from selenium import webdriver from selenium.webdriver import ActionChains from selenium.webdriver.common.by import By from selenium.webdriver.

我已经用python和selenium编写了一个脚本来登录网站。问题是我的脚本有时会成功登录,但大多数情况下它会遇到一个滑块,该滑块用于按下并向右滑动

  • 该滑块的图像:

如何让脚本向右滑动该按钮?

我试过:

from selenium import webdriver
from selenium.webdriver import ActionChains
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

def sign_in():
    driver.get("https://login.aliexpress.com/")
    wait.until(EC.frame_to_be_available_and_switch_to_it(wait.until(EC.visibility_of_element_located((By.CSS_SELECTOR, "#alibaba-login-box")))))
    wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, "input#fm-login-id"))).send_keys("someEmail")
    wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, "input#fm-login-password"))).send_keys("somePassword")
    wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, "button[class$='password-login']"))).click()

    #the following line is for handling the slider but it doesn't do anything

    item = wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, ".nc_wrapper .btn_slide")))
    ActionChains(driver).move_to_element(item).perform()

if __name__ == '__main__':
    driver = webdriver.Chrome()
    wait = WebDriverWait(driver,10)
    sign_in()
连接到该滑块的Html元素:

<div id="nc_1_n1t" class="nc_scale">
<div id="nc_1__bg" class="nc_bg" style="width: 0px;"></div>
<span id="nc_1_n1z" class="nc_iconfont btn_slide" data-spm-anchor-id="0.0.0.i1.3f9579f4qCwuHp" style="left: 0px;"></span>
<div id="nc_1__scale_text" class="scale_text slidetounlock"><span class="nc-lang-cnt" data-nc-lang="_startTEXT">Please slide to verify</span></div>
<div id="nc_1_clickCaptcha" class="clickCaptcha" style="top: -118px; height: 235px;">
<div class="clickCaptcha_text">
<b id="nc_1__captcha_text" class="nc_captch_text"></b>
<i id="nc_1__btn_2" class="nc_iconfont nc_btn_2 btn_refresh"></i>
</div>
<div class="clickCaptcha_img"></div>
<div class="clickCaptcha_btn"></div>
</div>
<div id="nc_1_imgCaptcha" class="imgCaptcha" style="top: -118px; min-height: 290px; height: 189px;">
<div class="imgCaptcha_text"><input id="nc_1_captcha_input" maxlength="6" type="text" style="ime-mode:disabled"></div>
<div class="imgCaptcha_img" id="nc_1__imgCaptcha_img"></div>
<i id="nc_1__btn_1" class="nc_iconfont nc_btn_1 btn_refresh" onclick="document.getElementById('nc_1__imgCaptcha_img').children[0].click()"></i>
<div class="imgCaptcha_btn">
<div id="nc_1__captcha_img_text" class="nc_captcha_img_text"></div>
<div id="nc_1_scale_submit" class="nc_scale_submit"></div>
</div>
</div>
<div id="nc_1_cc" class="nc-cc"></div>
<i id="nc_1__voicebtn" tabindex="0" role="button" class="nc_voicebtn nc_iconfont" style="display:none"></i>
<b id="nc_1__helpbtn" class="nc_helpbtn"><span class="nc-lang-cnt" data-nc-lang="_learning">help</span></b>
</div>


请用幻灯片验证



帮助

尝试使用下面的操作是c#代码供参考

//following code will click and hold the slider
string Xpath=""; //set xpath for desired element to be click and hold
Actions clickHold = new Actions(driver);
IWebElement element = driver.FindElement(By.XPath(Xpath));
clickHold.ClickAndHold(element).Perform();
按住滑块后,尝试将其移动到所需的偏移值

int x = 100; 
int y = 100;
Actions moveOffset = new Actions(driver);
moveOffset.MoveByOffset(x,y).Perform(); //set your suitable (x,y) offset value
下面是从左向右滑动操作的示例代码(java)

Actions slider=new Actions(driver);
slider.clickAndHold("xpath of slider");
slider.movebyoffset(x,y).build.perform(); 

代替“x”和“y”,您可以根据您的应用程序给出实际偏移值。

我无法在问题中链接的网站上显示滑块,因此我提供了一个使用另一个具有滑块元素的网站的解决方案(我假设该功能类似于aliexpress网站上的功能)

这里的关键部分是执行滑动动作的
行。我们必须确定两个具体因素:

  • 我们将要滑动的元素
  • 容纳此元素的容器
  • 找到这两个元素后,我们使用actions类单击并按住需要滑动的元素,然后沿x轴滑动包含元素的宽度(如使用
    slider\u container.size['width']
    所示),而不更改y轴

    这将解决您的滑动问题,但是您将有另一个问题,您需要确定是否显示了滑块,或者您已登录网站。为此,您需要一个预期条件来检查是否存在2个元素:

  • 滑块
  • 成功登录后希望看到的元素
  • 如果显示登录时希望看到的元素,则无需执行任何操作。如果显示滑块,则需要执行上述逻辑来滑动条

    *编辑*

    要进一步改进这一点,您可以将滑动代码置于如下所示的预期条件中:

    class wait_for_element_while_verifying_slider(object):
    
        def __init__(self, locator, slider_container_locator, slider_locator):
            self.locator = locator
            self.slider_container_locator = slider_container_locator
            self.slider_locator = slider_locator
    
        def __call__(self, _driver):
            try:
                return _driver.find_element(*self.locator)
            except (NoSuchElementException, StaleElementReferenceException):
                container = _driver.find_elements(*self.slider_container_locator)
                slider = _driver.find_elements(*self.slider_locator)
                if len(container) > 0 and len(slider) > 0:
                    actions = ActionChains(_driver)
                    actions.move_to_element(slider[0]).click_and_hold().move_by_offset(container[0].size['width'], 0).release().perform()
    
            return False
    
    这将搜索您希望在登录时显示的元素。如果您成功登录后希望看到的元素未显示,则它将尝试定位滑块元素,并与它们交互以处理幻灯片验证。请注意,一旦它尝试执行幻灯片验证,预期条件将返回False,这将迫使它检查预期登录元素是否再次显示

    您可以在代码中使用它,如下所示:

    # Instantiate objects
    driver = webdriver.Chrome()
    wait = WebDriverWait(driver, 10)
    
    # Load page and fill in input elements
    driver.get("http://kthornbloom.com/slidetosubmit/")
    driver.find_element(By.NAME, "name").send_keys("Fred")
    driver.find_element(By.NAME, "email").send_keys("fred@example.com")
    
    # Define slider elements and element that will be shown when you successfully log in
    SLIDER_CONTAINER = (By.CSS_SELECTOR, ".slide-submit")
    SLIDER = (By.CSS_SELECTOR, ".slide-submit-thumb")
    ELEMENT_TO_FIND = (By.XPATH, "//div[.=\"Looks Like You're Human!\"]")
    
    # Invoke the explicit wait that will deal with the slider if it is displayed
    wait.until(wait_for_element_while_verifying_slider(ELEMENT_TO_FIND, SLIDER_CONTAINER, SLIDER))
    
    上面的示例使用与上面相同的示例网站。要使其超时,您可以将
    元素\u To\u FIND
    更改为不存在的内容。要使其通过而不滑动,您可以将
    元素\u修改为\u FIND
    为:

    ELEMENT_TO_FIND = (By.XPATH, "//div[.=\"Slide To Submit\"]")
    
    使用您在评论中提供的代码,我希望以下内容可以在aliexpress网站上使用:

    # Define slider elements and element that will be shown when you successfully log in
    SLIDER_CONTAINER = (By.CSS_SELECTOR, ".nc-lang-cnt")
    SLIDER = (By.CSS_SELECTOR, ".nc_wrapper .btn_slide")
    ELEMENT_TO_FIND = (By.ID, "search-key")
    
    # Invoke the explicit wait that will deal with the slider if it is displayed
    wait.until(wait_for_element_while_verifying_slider(ELEMENT_TO_FIND, SLIDER_CONTAINER, SLIDER))
    

    其他功能包括鼠标按下(
    点击并按住()
    )、鼠标移动(
    按偏移量移动()
    )和鼠标向上(
    释放()
    )操作。是否可以共享用于登录的测试用户名和密码。也许您可以提供一个指向我可以使用的网站的url,并确保提供一个有效的解决方案?请不要为我显示滑块:(当您连续几次执行脚本时,会显示该滑块@Ardesco.Question更新以尝试帮助您解决此问题。您可能会使脚本更干净,但我将留给您:)
    # Define slider elements and element that will be shown when you successfully log in
    SLIDER_CONTAINER = (By.CSS_SELECTOR, ".nc-lang-cnt")
    SLIDER = (By.CSS_SELECTOR, ".nc_wrapper .btn_slide")
    ELEMENT_TO_FIND = (By.ID, "search-key")
    
    # Invoke the explicit wait that will deal with the slider if it is displayed
    wait.until(wait_for_element_while_verifying_slider(ELEMENT_TO_FIND, SLIDER_CONTAINER, SLIDER))