Python 嵌套字典和列表的单词计数器

我有一本这样的字典：

d = {'name1': {'details': ['something',
   'another thing',],
  'groups': ['first', 'second'],
 },
'name2': {'details': ['other details'],
  'groups': ['first', 'third'],
 }}

groups = ['first', 'second', 'third']

下面是一个列表：

d = {'name1': {'details': ['something',
   'another thing',],
  'groups': ['first', 'second'],
 },
'name2': {'details': ['other details'],
  'groups': ['first', 'third'],
 }}

groups = ['first', 'second', 'third']

我想计算一下每组被提及的次数，并得到以下结果：

counted = {'first': 2, 'second':1, third:1}

我尝试过循环，但出现了各种错误。

这样就可以了

import itertools
from collections import Counter
Counter(itertools.chain.from_iterable([x['groups'] for x in d.values()]))

输出

Counter({'first': 2, 'second': 1, 'third': 1})

---

您可以使用

列表理解
：

from collections import Counter
print(Counter([i for v in d.values() for i in v["groups"]]))
# Counter({'first': 2, 'second': 1, 'third': 1})

试试这个：

        d = {'name1': {'details': ['something',
   'another thing',],
  'groups': ['first', 'second'],
 },
'name2': {'details': ['other details'],
  'groups': ['first', 'third'],
 }}

counted = {}
for names in d.keys():
    for elements in d[names]["groups"]:
        if elements not in counted.keys():
            counted[elements] = 1
        else:
            counted[elements] += 1

print(counted)

您的
组
列表不是列表。这是一个元组（列表）。@jarmod，谢谢-typo:）